Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
Answer:
The answer is 0
Step-by-step explanation:
Answer:
first blank- 2 second blank- 3 1/2 or 4 may be 3 too
Step-by-step explanation:
well when you look at the shape you can go from a to b and count the blocks which it would be 2
and you would want to do the same thing with C,D
Answer:
18,720
Step-by-step explanation:
there are approximately 52 weeks in a year
