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3 years ago

Can some please help me!!!! I need this asap!

Mathematics

1 answer:

Alecsey [184]3 years ago

6 0

Answer:

A= -1,4 B=2,3 C=3,0 D=-1,-1

Step-by-step explanation:

idk what your looking for but I hope this helps

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Find the area of quadrilateral with vertices at points (3,0)(4,5)(-1,4)(-2,-1)

guapka [62]

Answer: 20

Step-by-step explanation:

Let 's complete our quadrilateral to a rectangle ; and subtract from it the area highlighted in red

$\displaystyle \rm S_{\diamond}=6\cdot 5 =30 \\\\ S_{ABCD}=30-(5:2+5:2+5:2+3:2+1\cdot1)=30-(7,5+1,5+1)=\\\\30-10=20 \\\\ S_{ABCD}=20$

4 0

3 years ago

Read 2 more answers

Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25

aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The mean time for the component failure is 2500 hours.

This means that $m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004$

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

$P(X > x) = e^{-0.0004*5000} = 0.1353$

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0

2 years ago

Use the distance formula to calculate the length of the leg CD

Karo-lina-s [1.5K]

To calculate the distance between two points on the coordinate system you have to use the following formula:

$d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}$

Where

d represents the distance between both points.

(x₁,y₁) are the coordinates of one of the points.

(x₂,y₂) are the coordinates of the second point.

To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph

C(2,-1)

D(-1,-2)

Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)

$\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}$

The length of CD is √10 units ≈ 3.16 units

6 0

1 year ago

1) 2 (x+3) +3 (5-x)=

Ugo [173]

Answer:

Below

Step-by-step explanation:

1. 2 (x+3) +3 (5-x)=

Simplifying

2(x + 3) + 3(5 + -1x) = 0

Reorder the terms:

2(3 + x) + 3(5 + -1x) = 0

(3 * 2 + x * 2) + 3(5 + -1x) = 0

(6 + 2x) + 3(5 + -1x) = 0

6 + 2x + (5 * 3 + -1x * 3) = 0

6 + 2x + (15 + -3x) = 0

Reorder the terms:

6 + 15 + 2x + -3x = 0

Combine like terms: 6 + 15 = 21

21 + 2x + -3x = 0

Combine like terms: 2x + -3x = -1x

21 + -1x = 0

Solving

21 + -1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-21' to each side of the equation.

21 + -21 + -1x = 0 + -21

Combine like terms: 21 + -21 = 0

0 + -1x = 0 + -21

-1x = 0 + -21

Combine like terms: 0 + -21 = -21

-1x = -21

Divide each side by '-1'.

x = 21

Simplifying

x = 21

2. 3 (y+2) -4y=-24y

Simplifying

3(y + 2) + -4y = -24y

Reorder the terms:

3(2 + y) + -4y = -24y

(2 * 3 + y * 3) + -4y = -24y

(6 + 3y) + -4y = -24y

Combine like terms: 3y + -4y = -1y

6 + -1y = -24y

Solving

6 + -1y = -24y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '24y' to each side of the equation.

6 + -1y + 24y = -24y + 24y

Combine like terms: -1y + 24y = 23y

6 + 23y = -24y + 24y

Combine like terms: -24y + 24y = 0

6 + 23y = 0

Add '-6' to each side of the equation.

6 + -6 + 23y = 0 + -6

Combine like terms: 6 + -6 = 0

0 + 23y = 0 + -6

23y = 0 + -6

Combine like terms: 0 + -6 = -6

23y = -6

Divide each side by '23'.

y = -0.2608695652

Simplifying

y = -0.2608695652

3. -(x+2) -2(1-x)=

Simplifying

-1(x + 2) + -2(1 + -1x) = 0

Reorder the terms:

-1(2 + x) + -2(1 + -1x) = 0

(2 * -1 + x * -1) + -2(1 + -1x) = 0

(-2 + -1x) + -2(1 + -1x) = 0

-2 + -1x + (1 * -2 + -1x * -2) = 0

-2 + -1x + (-2 + 2x) = 0

Reorder the terms:

-2 + -2 + -1x + 2x = 0

Combine like terms: -2 + -2 = -4

-4 + -1x + 2x = 0

Combine like terms: -1x + 2x = 1x

-4 + 1x = 0

Solving

-4 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.

-4 + 4 + 1x = 0 + 4

Combine like terms: -4 + 4 = 0

0 + 1x = 0 + 4

1x = 0 + 4

Combine like terms: 0 + 4 = 4

1x = 4

Divide each side by '1'.

x = 4

Simplifying

x = 4

4. whats ? is the equation

6 0

3 years ago

A manufacturer makes closed cubic containers from sheet metal. How many square centimeters of sheet metal will a 27,000 cm 3 con

dezoksy [38]

let's recall that a cube is just a rectangular prism with all equal sides, check picture below.

$\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180$

6 0

3 years ago