Because there are 12 inches in a foot, consider an inch as 1/12 of a foot. Subtract 23'-6" from 90'-1" using fractions.

How would i solve for x and y in 3x+2y=17 and 2x-y=2 by using substitution

maxonik [38]

I’ll do an example problem, and I challenge you to do this on your own!
4x+6y=23
7y-8x=5
Solving for y in 4x+6y=23, we can separate the y by subtracting both sides by 4x (addition property of equality), resulting in 6y=23-4x. To make the y separate from everything else, we divide by 6, resulting in (23-4x)/6=y. To solve for x, we can do something similar - subtract 6y from both sides to get 23-6y=4x. Next, divide both sides by 4 to get (23-6y)/4=x.

Since we know that (23-4x)/6=y, we can plug that into 7y-8x=5, resulting in
7*(23-4x)/6-8x=5
= (161-28x)/6-8x
Multiplying both sides by 6, we get 161-28x-48x=30
= 161-76x
Subtracting 161 from both sides, we get -131=-76x. Next, we can divide both sides by -76 to separate the x and get x=131/76. Plugging that into 4x+6y=23, we get 4(131/76)+6y=23. Subtracting 4(131/76) from both sides, we get
6y=23-524/76. Lastly, we can divide both sides by 6 to get y=(23-524/76)/6

Good luck, and feel free to ask any questions!

4 0

3 years ago

Answer the question on the attachement

Mama L [17]

Answer: 6 cups of water

7 0

3 years ago

Dave drove from town A to town B at an average speed of 70km/h. At the same time, Peter drove from town B to town A along the sa

padilas [110]

Remark

Every so often, someone comes up with a variation on the most basic physics formula d = r * t

We will need to think up three formulas to solve this. We may not need all three, but we need them to see how the problem works.

Formula one

Where and when do they meet.

The meet after 6 minutes before Peter finished. Peter finished the course after 24 minutes. Six minutes before that they met. That's 18 after starting they met.

After 18 minutes they completed the course between them

hours to meeting = 18/60 = 0.3 hours

Dave met Peter after a distance of r * t = 70*0.3 = 21 km

Peter had traveled at some speed for 21 minutes = r1 * 0.3 = d1

So the total distance d = is 21 km + r1*0.3 = d

Six minutes later

Peter's Progress

6 minutes later Peter finishes distance D. He does this in 24 minutes.

d = r1 * 24 = r1*24/60 = r1 * 0.4 hours

Dave's Progress

d - 2 = 70 km/hr * 0.4 hr

d - 2 = 28 km

d = 28 + 2 = 30 km

Note this is the total distance that both Peter and Dave travelled.

Question A

How far had Dave gone before he met Peter.

Time = 18 minutes = 0.3 of an hour.

r = 70 km / hour

r = 70 km/hour * 0.3 hour

d = 21 km They met after Dave drove 21 km <<< Answer

Question B

Peter's Rate

d = 30 km

t = 24 minutes = 24/60 = 0.4 hours.

r = 30/0.4 = 75 km/hr. <<< Peter's Speed Answer

5 0

3 years ago

Sia weighs 4.5 kg more than raima. If their total weight is 140kg. find Sia's weight

Simora [160]

74.5kg

Step-by-step explanation:

(140kg ÷ 2 = 70kg) 70kg - 4.5kg = 65.5 (65.5 is raima's weight) 70kg +4.5kg = 74.5kg (74.5kg is sia's weight)

8 0

2 years ago

What is the solution to the system of equations? 2x – y = 7 y = 2x + 3

Mars2501 [29]

Hi:))
Additional solutions:)

6 0

2 years ago