Question

X^4-3x^2+2=0 Đặt ẩn t

Answer 1

Answer:

$x_{1} = - \sqrt{2} \: .\: x_{2} = - 1 \: . \: x_{3} = 1 \: . \: x_{4} = \sqrt{2}$

Step-by-step explanation:

x⁴ - 3x² + 2 = 0

x^2×2 - 3x² + 2 = 0

(x²)² - 3x² + 2 = 0

t² - 3t + 2 = 0

t = 1, t = 2

x² = 1, x² = 2

x = -1, x = 1

x = - square root 2, x = square root 2

$x_{1} = - \sqrt{2} \: .\: x_{2} = - 1 \: . \: x_{3} = 1 \: . \: x_{4} = \sqrt{2}$