Answer:
a
Step-by-step explanation:
Vecayse Sjuare tmes
F(x) = k(x+2)(2x-1)(x-3), where k is some constant
= k(2x^3-3x^2-11x+6)
= k(-2x^3+3x^2+11x-6)
k defines some vertical stretch, so there are an infinitely many solutions for f(x).
The answer is 244 because you add 35 to 287 then subtract 78 and it equals 244




For either square root to exist, you require that

. This is true for all

, since

is always non-negative. This means the domain of

as a function of

is all real numbers, or

or

.
Now, because

is non-negative, and the smallest value it can take on is 7, it follows that the minimum value for the positive square root must be

, while the maximum value of the negative root must be

. This means the range is

, or

, or
![(-\infty,-\sqrt7]\cup[\sqrt7,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-%5Csqrt7%5D%5Ccup%5B%5Csqrt7%2C%5Cinfty%29)
.