The first part of the second line, she left the -5 there. The correct work and solution should be this:
5(2x-1)-3x=5x+9
<span><span>7x</span>−5</span>=<span><span>5x</span>+<span>9
</span></span>2x-5=9
2x=14
x=7
Answer:
b
Step-by-step explanation:
did the unit test
Answer:
80°
Step-by-step explanation:
Let the angle be x then four times it's complement plus 60, that is
4(90 - x) + 60 ← is it's supplement
Supplementary angles sum to 180°
Sum the angle and it's supplement and equate to 180
x + 4(90 - x) + 60 = 180 ← distribute and simplify left side
x + 360 - 4x + 60 = 180
- 3x + 420 = 180 ( subtract 420 from both sides )
- 3x = - 240 ( divide both sides by - 3 )
x = 80
The required angle = x = 80°
supplement = 4(90 - 80) + 60 = 4 × 10 + 60 = 40 + 60 = 100°
Answer:
[Vertex form]
Step-by-step explanation:
Given function:

We need to find the vertex form which is.,

where
represents the co-ordinates of vertex.
We apply completing square method to do so.
We have

First of all we make sure that the leading co-efficient is =1.
In order to make the leading co-efficient is =1, we multiply each term with -3.


Isolating
and
terms on one side.
Subtracting both sides by 15.


In order to make the right side a perfect square trinomial, we will take half of the co-efficient of
term, square it and add it both sides side.
square of half of the co-efficient of
term = 
Adding 36 to both sides.


Since
is a perfect square of
, so, we can write as:

Subtracting 21 to both sides:


Dividing both sides by -3.

[Vertex form]
3a to the power of 2 plus 5a minus 2