Question

Find all real solutions x to 4^x - 2^x = 56.

Answer 1

Since the bases are the same, set the exponents equal to each other. X = 3

Answer 2

$4^{x}$ ↓
 $(( 2^{x} )) ^2$↓
$y^{x} = w$↓
$w^{2} - w - 56 = 0$↓
w - 8  &  w + 7↓
w(1) = 8 → w(1) = $2^{x1} = 8$ x(1) = 3↓
w(2) = -7 → w(2) = $2^{x2} = -7$
So, therefore the value of "x" would have to be "3"