Question

Find 3 consecutive even integers such that the sum of the first and third is -16.

Answer 1

Answer:

1st number = -10

2nd number = -8

3rd number = -6

Step-by-step explanation:

Take the first number as x

The next consecutive even number will be x+2

The 3rd even number will be x+4.

Sum of 1st and 3rd number = -16

(x) + (x+4) = -16

x+ x+4 = -16

2x + 4 = -16

2x = -16 -4

2x = -20

x = $\frac{-20}{2}$

x = -10

2nd number = x+ 2

                     = -10 + 2

                     = -8

3rd number = x + 4

                    = -10 + 4

                    = -6

Hope this helps.