Zero degree celcius = 273.15 degree kelvin
Simply, to get the value of 45.1 degree celcius in kelvin, we will add 273.15 to the given value (45.1).
Degree in kelvin = 45.1 + 273.15 = 318.25 degree kelvin
Approximating to the nearest tenth, the value will be 318.3 degree kelvin
Answer:
-372000 J or -372 KJ
Explanation:
We have the electrochemical reaction as;
Mg(s) + Fe^2+(aq)→ Mg^2+(aq) + Fe(s)
We must first calculate the E∘cell from;
E∘cathode - E∘anode
E∘cathode = -0.44 V
E∘anode = -2.37 V
Hence;
E∘cell = -0.44 V -(-2.37 V)
E∘cell = 1.93 V
n= 2 since two electrons were transferred
F=96,500C/(mol e−)
ΔG∘=−nFE∘
ΔG∘= -( 2 * 96,500 * 1.93)
ΔG∘= -372000 J or -372 KJ
Answer:
The answer is
<h3>3.75 × 10²⁴ atoms of Al</h3>
Explanation:
To find the number of atoms of Al given it's number of moles we use the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
n = 6.23 mol
We have
N = 6.23 × 6.02 × 10²³
We have the final answer as
<h3>3.75 × 10²⁴ atoms of Al</h3>
Hope this helps you