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galben [10]
2 years ago
11

Covert 645g of CuCl2 to mole

Chemistry
1 answer:
shepuryov [24]2 years ago
8 0

Answer:

kombinasi kuda-kuda belakang

Explanation:

maaf kalau salahnya

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Using 273.15 K as the value for Zero degree Celsius convert 45.1° C to Kelvin. 6.05 K 318 K 318.3 K 1.23 x 104 K
OLEGan [10]
Zero degree celcius = 273.15 degree kelvin

Simply, to get the value of 45.1 degree celcius in kelvin, we will add 273.15 to the given value (45.1).

Degree in kelvin = 45.1 + 273.15 = 318.25 degree kelvin

Approximating to the nearest tenth, the value will be 318.3 degree kelvin
8 0
3 years ago
Free-energy change, ΔG∘, is related to cell potential, E∘, by the equation ΔG∘=−nFE∘ where n is the number of moles of electrons
elena-s [515]

Answer:

-372000 J or -372 KJ

Explanation:

We have the electrochemical reaction as;

Mg(s)  +  Fe^2+(aq)→  Mg^2+(aq)  +   Fe(s)

We must first calculate the E∘cell from;

E∘cathode -  E∘anode

E∘cathode = -0.44 V

E∘anode = -2.37 V

Hence;

E∘cell = -0.44 V -(-2.37 V)

E∘cell = 1.93 V

n= 2 since two electrons were transferred

F=96,500C/(mol e−)

ΔG∘=−nFE∘

ΔG∘= -( 2 * 96,500 * 1.93)

ΔG∘= -372000 J or -372 KJ

4 0
2 years ago
How many grams of hydrochloric acid are in 0.500 L of solution
neonofarm [45]

Answer:

500 grams?

Explanation:

3 0
3 years ago
Given 6.23 mol Al find the atoms of Al
swat32

Answer:

The answer is

<h3>3.75 × 10²⁴ atoms of Al</h3>

Explanation:

To find the number of atoms of Al given it's number of moles we use the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 6.23 mol

We have

N = 6.23 × 6.02 × 10²³

We have the final answer as

<h3>3.75 × 10²⁴ atoms of Al</h3>

Hope this helps you

3 0
2 years ago
I need help I’ll give you brainliest
Svetlanka [38]

Answer:

2 or 3 i think

Explanation:

5 0
3 years ago
Read 2 more answers
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