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2 years ago

Given that blood exerts the same osmotic pressure as a 0.15 M NaCl solution, which solution could be the isotonic solution

Chemistry

1 answer:

bulgar [2K]2 years ago

8 0

Answer:

0.15 (M) of NaCl

Explanation:

An isotonic solution is defined as the solution having the same osmolarity, or the same solute concentration, as the another solution. If the two solutions are to be separated by any semipermeable membrane, then water will start flowing in equal parts from each solution and also into the other.

In the context, since it is given that the red blood cells exerts the same osmotic pressure as a 0.15 (M) of NaCl solution.

Thus, 0.15 (M) of NaCl is a isotonic solution.

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This is the number of protons and neutrons i the nucleus of any atom

icang [17]

Answer:

The mass number is defined as the total number of protons and neutrons in an atom. Consider Table below which shows data from the first six elements of the periodic table. Consider the element helium. Its atomic number is 2, so it has two protons in its nucleus.

Explanation:

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2 years ago

La lluvia acida es un fenomeno a nivel local o Regional?

Lesechka [4]

Answer:

Regional

Explanation:

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2 years ago

What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? Ass

Nataly [62]

Answer:

Ba^2+(aq) + 2OH-(aq) + 2H+(aq) + SO4^2-(aq) → BaSO4(s) + 2H2O(l)

Explanation:

Step 1: Data given

the contribution of protons from H2SO4 is near 100 %.

Step 2: The unbalanced equation

.Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + H2O(l)

Step 3: Balancing the equation

On the left side we have 4x H (2x in Ba(OH)2 and 2x in H2SO4). On the right side, we have 2x H (in H2O).

To balance the amount of H on both sides, we have to muliply H2O (on the right side) by 2.

Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + 2H2O(l)

Step 4: The net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.

Ba^2+(aq) + 2OH-(aq) + 2H+(aq) + SO4^2-(aq) → BaSO4(s) + 2H2O(l)

After canceling those spectator ions in both side, look like this:

Ba^2+(aq) + 2OH-(aq) + 2H+(aq) + SO4^2-(aq) → BaSO4(s) + 2H2O(l)

4 0

3 years ago

The decomposition reaction of N2O5 in carbon tetrachloride is 2N2O5−→−4NO2+O2. The rate law is first order in N2O5. At 64 °C the

Mademuasel [1]

Answer:

(a) rate = 4.82 x 10⁻³s⁻¹ [N2O5]

(b) rate = 1.16 x 10⁻⁴ M/s

(d) rate = 5.80 x 10⁻⁵ M/s

Explanation:

We are told the rate law is first order in N₂O₅, and its rate constant is 4.82 x 10⁻³s⁻¹ . This means the rate is proportional to the molar concentration of N₂O₅, so

(a) rate = k [N2O5] = 4.82 x 10⁻³s⁻¹ x [N2O5]

(b) rate = 4.82×10⁻³s⁻¹ x 0.0240 M = 1.16 x 10⁻⁴ M/s

(c) Since the reaction is first order if the concentration of N₂O₅ is double the rate will double too: 2 x 1.16 x 10⁻⁴ M/s = 2.32 x 10⁻⁴ M/s

(d) Again since the reaction is halved to 0.0120 M, the rate will be halved to

1.16 x 10⁻⁴ M/s / 2 = 5.80 x 10⁻⁵ M/s

3 0

2 years ago

Read 2 more answers

A container was found in the home of the victim that contained 120 g of ethylene glycol in 550 g of liquid. How many drinks, eac

Andrei [34K]

Answer:

0.432 drinks are toxic

Explanation:

The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):

1.11g/mL * (0.1mL / kg) = 0.111g/kg

If the victim weighs 85kg, its letal dose is:

85kg * (0.111g/kg) = 9.435g of ethylene glycol

Using the concentration of ethylene glycol in the liquid:

9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.

The drinks are:

43.2g of liquid * (1 drink / 100 g) =

<h3>0.432 drinks are toxic</h3>

5 0

3 years ago