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3 years ago

Given that blood exerts the same osmotic pressure as a 0.15 M NaCl solution, which solution could be the isotonic solution

Chemistry

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

0.15 (M) of NaCl

Explanation:

An isotonic solution is defined as the solution having the same osmolarity, or the same solute concentration, as the another solution. If the two solutions are to be separated by any semipermeable membrane, then water will start flowing in equal parts from each solution and also into the other.

In the context, since it is given that the red blood cells exerts the same osmotic pressure as a 0.15 (M) of NaCl solution.

Thus, 0.15 (M) of NaCl is a isotonic solution.

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3 years ago

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galina1969 [7]

Answer:

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Explanation:

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3 years ago

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Arte-miy333 [17]

Answer:

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Explanation:

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3 years ago

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melomori [17]

Answer:

$6.022\cdot 10^{23}$ molecules of nitrogen gas

Explanation:

In order to convert the mass of a given compound into the number of molecules, we need to:

identify the number of moles of a given compound dividing its mass by the molar mass, $n = \frac{m}{M}$ ,
multiply the number of moles by the Avogadro's constant which tells us that 1 mole contains $N_A = 6.022\cdot 10^{23}$ molecules.

In this problem:

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The number of particles is then found by:

$N_{N_2} = n_{N_2}\cdot N_A = \frac{m_{N_2}}{M_{N_2}} N_A = \frac{28 g}{28.01 g/mol}\cdot 6.022\cdot 10^{23} mol^{-1} = 6.022\cdot 10^{23}$

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dalvyx [7]

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