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3 years ago

Given that blood exerts the same osmotic pressure as a 0.15 M NaCl solution, which solution could be the isotonic solution

Chemistry

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

0.15 (M) of NaCl

Explanation:

An isotonic solution is defined as the solution having the same osmolarity, or the same solute concentration, as the another solution. If the two solutions are to be separated by any semipermeable membrane, then water will start flowing in equal parts from each solution and also into the other.

In the context, since it is given that the red blood cells exerts the same osmotic pressure as a 0.15 (M) of NaCl solution.

Thus, 0.15 (M) of NaCl is a isotonic solution.

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The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process.... In the first step, manganes

frez [133]

Answer : The mass of $MnCO_3$ required are, 35 kg

Explanation :

First we have to calculate the mass of $MnO_2$ .

The first step balanced chemical reaction is:

$2MnCO_3+O_2\rightarrow 2MnO_2+2CO_2$

Molar mass of $MnCO_3$ = 115 g/mole

Molar mass of $MnO_2$ = 87 g/mole

Let the mass of $MnCO_3$ be, 'x' grams.

From the balanced reaction, we conclude that

As, $(2\times 115)g$ of $MnCO_3$ react to give $(2\times 87)g$ of $MnO_2$

So, $xg$ of $MnCO_3$ react to give $\frac{(2\times 87)g}{(2\times 115)g}\times x=0.757xg$ of $MnO_2$

And as we are given that the yield produced from the first step is, 65 % that means,

$60\% \text{ of }0.757xg=\frac{60}{100}\times 0.757x=0.4542xg$

The mass of $MnO_2$ obtained = 0.4542x g

Now we have to calculate the mass of $Mn$ .

The second step balanced chemical reaction is:

$3MnO_2+4Al\rightarrow 3Mn+2Al_2O_3$

Molar mass of $MnO_2$ = 87 g/mole

Molar mass of $Mn$ = 55 g/mole

From the balanced reaction, we conclude that

As, $(3\times 87)g$ of $MnO_2$ react to give $(3\times 55)g$ of $Mn$

So, $0.4542xg$ of $MnO_2$ react to give $\frac{(3\times 55)g}{(3\times 87)g}\times 0.4542x=0.287xg$ of $Mn$

And as we are given that the yield produced from the second step is, 80 % that means,

$80\% \text{ of }0.287xg=\frac{80}{100}\times 0.287x=0.2296xg$

The mass of $Mn$ obtained = 0.2296x g

The given mass of Mn = 8.0 kg = 8000 g (1 kg = 1000 g)

So, 0.2296x = 8000

x = 34843.20 g = 34.84 kg = 35 kg

Therefore, the mass of $MnCO_3$ required are, 35 kg

4 0

3 years ago

Read 2 more answers

Magnesium hydroxide reacts with hydrogen chloride, a double-displacement reaction occurs and produces magnesium chloride and wat

Natalija [7]

Explanation:

magnesium Hydroxide + Hydrochloric react together and give us magnesium chloride + water

5 0

2 years ago

If the mass of a box is 140 g, and the volume is 8 cm3, then the density of the box = ? socratic.org

Ksivusya [100]

Answer:

17.5 g/cm³

Explanation:

We can solve this particular problem by keeping in mind the definition of density:

Density = mass / volume

As the problem gives us both the mass and the volume of the box, we can now proceed to calculate the density:

Density = 140 g / 8 cm³

Density = 17.5 g/cm³

The density of the box is 17.5 g/cm³.

4 0

2 years ago

The concentration of pb2+ in a commercially available standard solution is 1.00 mg/ml. what volume of this solution should be di

Vanyuwa [196]

The concentration of pb2+ = 1.00mg/ml Diluted Solution is 6.0 x 102 ml = 612 ml Volume of the concentration of pb2+ is 0.054 mg/l is v (vL)(1.00mg/ml) = (.612L)(0.054mg/l) Volume = 0.033048L Volume of the concentration of pb2+ is 0.054 mg/l = 33.048 ml.

3 0

3 years ago

he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.

m_a_m_a [10]

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number $(\bar{M_n}) = 1000000 \frac{g}{mol}$