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ruslelena [56]
4 years ago
13

When hydrochloric acid reacts with sodium sulfide, hydrogen sulfide gas and sodium chloride are produced. How many moles of H2S

will be generated by 2.56 moles of HCl? 2HCl + Na2S → H2S + 2NaCl
A 10 liters
B 0.1 liters
C 40 liters
D 20 liters
Chemistry
1 answer:
lidiya [134]4 years ago
5 0
Well 1.28 mol of H2S will be produce but it didn't said anything about that where the experiment happens (in STP situation (which seems not to be true ) or not )
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Answer: Law of conservation of mass explains these observations.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.

In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.

2Mg+O_2\rightarrow 2MgO

Mass of reactants= mass of Mg+ mass of O_2  = 48 g + 32 g = 80 g

Mass of products = mass of MgO = 80 g

Thus mass of reactants is equal to mass of products, thus law of conservation of mass is obeyed.

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A plane traveling at 80m/s lands on a runway and comes to rest after 10 seconds. What was the planes deceleration?
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Balance each of the following in BASE: Show work
kupik [55]

Answer : The balanced chemical equation in a basic solution are,

(A) 2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2

(B) 2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-

(C) 4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3

(D) Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-

Explanation :

<u>(A) The given chemical reaction is :</u>

CrO_4^{2-}(aq)+Cu(s)\rightarrow Cr(OH)_3(s)+Cu(OH)_2(s)

The oxidation-reduction half reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : CrO_4^{2-}+4H_2O+3e^-\rightarrow Cr^{3+}+8OH^-

In order to balance the electrons, we multiply the oxidation reaction by 3 and reduction reaction by 2 then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr^{3+}+16OH^-+3Cu^{2+}

or,

2CrO_4^{2-}+8H_2O+3Cu\rightarrow 2Cr(OH)_3+4OH^-+3Cu(OH)_2

<u>(B) The given chemical reaction is :</u>

NO_2(g)\rightarrow NO_3^-(aq)+NO_2^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : NO_2+2OH^-\rightarrow NO_3^-+H_2O+1e^-

Reduction : NO_2+1e^-\rightarrow NO_2^-

The electrons in both the reactions are balanced. Now added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

2NO_2+2OH^-\rightarrow NO_3^-+H_2O+NO_2^-

<u>(C) The given chemical reaction is :</u>

Zn(s)+NO_3^-(aq)\rightarrow Zn(OH)_4^{2-}(aq)+NH_3(g)

The oxidation-reduction half reaction will be :

Oxidation : Zn+4OH^-\rightarrow [Zn(OH)_4]^{2-}+2e^-

Reduction : NO_3^-+6H_2O+8e^-\rightarrow NH_3+9OH^-

In order to balance the electrons, we multiply the oxidation reaction by 4 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

4Zn+7OH^-+NO_3^-+6H_2O\rightarrow 4[Zn(OH)_4]^{2-}+NH_3

<u>(D) The given chemical reaction is :</u>

Br_2(l)\rightarrow BrO_3^-(aq)+Br^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : Br_2+12OH^-\rightarrow 2BrO_3^-+6H_2O+10e^-

Reduction : Br_2+2e^-\rightarrow 2Br^-

In order to balance the electrons, we multiply the reduction reaction by 5 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

Br_2+12OH^-+5Br_2\rightarrow 2BrO_3^-+6H_2O+10Br^-

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Answer:

It is a group of compound derived from alkanes containing one or more halogens .

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