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Lubov Fominskaja [6]
1 year ago
8

a technician mixes 80 ml of a 5% solution with 10 ml of water. what is the final percentage strength of the solution prepared?

Chemistry
1 answer:
Vinvika [58]1 year ago
5 0

A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

given that :

8 ml of a 5 % solution mix with 10 ml . that means the 80 mL of 5 % solution is diluted with water of 10 mL

therefore, 80 × 5 = 10 × x %

x % = 40 %

Therefore, the final percentage strength of the solution is 40 %

Thus, A technician mixes 80 ml of a 5% solution with 10 ml of water.  the final percentage strength of the solution prepared is 40 %.

To learn more about percentage strength here

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32 g of sulfur will react with 48 g of oxygen to produce 80 g of sulfur trioxide. If 32 g of sulfur and 100 g of oxygen are plac
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Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

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For 0.998 moles S there will react 0.998 moles SO3

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Mass SO3 = 0.998 moles * 80.07 g/mol

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There will be produced 80 grams of SO3

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

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