Light waves, since light is used in electricity! :D
Chemical reaction: NaHCO₃ + HCl → NaCl + H₂CO₃.
H₂CO₃ → H₂O + CO₂.
If amount of sodium bicarbonate (NaHCO₃) is 1 mol, then from from reaction we can calculate amount of carbon dioxide:
n(NaHCO₃) . n(CO₂) = 1 : 1.
n(CO₂) = 1 mol.
At standard pressure and temperature:
V(CO₂) = n(CO₂) · Vm
V(CO₂) = 1 mol · 22,4 L/mol.
V(CO₂) = 22,4 L.
Answer:
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
Explanation:
First equation:
The reactants propane and water react to form the products CO and H2
C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)
Second equation:
The products CO and H2 will react
CO(g) + H2O(g) → H2(g) + CO2(g)
We should multiply the equation by 3 (to equal the products of the first equation)
3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)
Add the second to the first equation:
C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)
The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)
Given:
P1 = 50 kPa
V1 = 5.0 L
P2 = 125 kPa
V2 = ?
Boyle's Law
P1V1 = P2V2
50 * 5 = 125 * V2
250 = 125 * V2
250 / 125 = V2
2 = V2
Answer is letter C. 2.0 L