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zhannawk [14.2K]
3 years ago
10

Hai quả cầu nhỏ hoàn toàn giống nhau, mang điện tích q1, q2 đặt trong chân không cách nhau 20cm thì hút nhau F = 5×10^-5. đặt và

o giữa hai quả cầu tấm thủy tinh dày 5 cm có hằng số điện môi là 4. tính lực tác dụng giữa hai quả cầu
Physics
1 answer:
seropon [69]3 years ago
8 0

Answer:

Hai quả cầu nhỏ hoàn toàn giống nhau, mang điện tích q1, q2 đặt trong chân không cách nhau 20cm thì hút nhau F = 5×10^-5. đặt vào giữa hai quả cầu tấm thủy tinh dày 5 cm có hằng số điện môi là 4. tính lực tác dụng giữa hai quả cầu

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I think its 9.0397 Ohms

Explanation:

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If he completes the 200 m dash in 23 s and runs at constant speed throughout the race, what is his centripetal acceleration as h
Blababa [14]

Incomplete question.The complete one is here

A runner taking part in the 200m dash must run around the end of a track that has a circular arc with a radius curvature of 30m. The runner starts the race at a constant speed. If she completes the 200m dash in 23s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track?

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a_c=2.523m/s^2

Explanation:

Given data

L_{length}=200m\\r_{radius}=30m\\t_{time}=23s

Required

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Solution

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V_{velocity}=\frac{L_{length}}{t_{time}}\\V_{velocity}=\frac{200m}{23s}\\V_{velocity}=8.7m/s

The centripetal acceleration is given by:

a_{c}=\frac{V_{velocity}^2}{r_{radius}}\\ a_c=\frac{(8.7m/s)^2}{30m}\\ a_c=2.523m/s^2

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3 years ago
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