Answer:
5.79*10⁻⁹ m is the uncertainty in the position.
Explanation:
Heisenberg's uncertainty principle assumes that it is not possible to know exactly all the data regarding the behavior of particles. In other words, at the subatomic level, it is impossible to know at the same moment where a particle is, how it moves and what its speed is.
So, Heisenberg's Uncertainty Principle gives a relationship between the standard deviation of an object's position and its momentum.
Δp*Δx= h/(4π)
where
- Δp the standard deviation of the object's momentum,
- Δx the standard deviation of the object's position,
- h=6.63*10⁻³⁴ J.s is the Planck's constant.
By definition, the momentum of the electron equals the product of its mass and velocity. So, being the mass constant, you can said:
Δp= m*Δv
Replacing in the expresion of the Heisenberg's Uncertainty Principle:
m*Δv*Δx= h/(4π)
Then you know:
- m=9.11*10⁻³¹ kg
- Δv=0.01*10⁶ m/s
- h=6.63*10⁻³⁴ J.s= 6.63*10⁻³⁴ (N*m)*s=6.63*10⁻³⁴ [(kg*m*s⁻²)*m]*s= 6.63*10⁻³⁴ kg*m²*s⁻¹
Replacing:
*Δx=6.63*10⁻³⁴ kg*m²*s⁻¹/(4π)
Taking π=3.14 and solving:
Δx
Δx=5.79*10⁻⁹ m
<u><em>5.79*10⁻⁹ m is the uncertainty in the position.</em></u>
Answer:
K_b = 78 J
Explanation:
For this exercise we can use the conservation of energy relations
starting point. Lowest of the trajectory
Em₀ = K = ½ mv²
final point. When it is at tea = 50º
Em_f = K + U
Em_f = ½ m v_b² + m g h
where h is the height from the lowest point
h = L - L cos 50
Em_f = ½ m v_b² + mg L (1 - cos50)
energy be conserve
Em₀ = Em_f
½ mv² = ½ m v_b² + mg L (1 - cos50)
K_b = ½ m v_b² + mg L (1 - cos50)
let's calculate
K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)
K_b = 36 +42.0
K_b = 78 J
Yo, I assumed that this situation occurs on Earth otherwise the answer would be different.
Answer:
Yeah whats it doing for you?
Answer:
parasites are creatures the gain benefit off of other animals usually harming them eg:ticks on dogs