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AlekseyPX
2 years ago
7

Bro i need help omg.

Physics
2 answers:
sergey [27]2 years ago
8 0

Answer:

25.

Explanation:

olga nikolaevna [1]2 years ago
4 0

5

because you're taking off the front number which is one

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A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
2 years ago
Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would
Tatiana [17]

Answer:

<h3>The power of headlight in series connection is 29.64 W</h3>

Explanation:

Given :

Power of headlight P_{1} = 30 W

Power of starter P_{2} = 2500 W

Voltage of headlight and starter V = 12 V

From equation of power,

 P = \frac{V^{2} }{R}

 R = \frac{V^{2} }{P}

For finding the resistance of headlight and starter,

⇒ For headlight,

 R_{1}  = \frac{144}{30} = 4.8 Ω

⇒ For starter,

R_{2} = \frac{144}{2500} = 0.057 Ω

Since equivalent resistance,

R_{eq} = R_{1} + R_{2} + ........

R_{eq} = 4.8 +0.057 = 4.857 Ω

So power in series is given by,

 P_{s } = \frac{V^{2} }{R_{eq} }  = \frac{144}{4.857}

 P_{s } = 29.64 W

8 0
3 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object’s acceleration?
Shtirlitz [24]

Answer:

6 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

Acceleration is defined mathematically as:

Acceleration (a) = Velocity (v) /time (t)

a = v /t

With the above formula, we can obtain the acceleration of the object as follow:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

a= v/t

a= 30/5

a = 6 m/s²

Therefore, the acceleration of the object is 6 m/s² due East.

7 0
3 years ago
How is electron movement related to the bonding in sodium chloride?
irina1246 [14]
I think its c sorry if I’m wrong
8 0
3 years ago
Read 2 more answers
On which planet would your weight be the most and the least?
hoa [83]

Answer:

Jupiter and neptune

Explanation:

6 0
3 years ago
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