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viva [34]
4 years ago
7

For most people, the most effective way to save is:

Business
1 answer:
sergeinik [125]4 years ago
8 0
For most people, the most effective way to save is to deposit extra money into a savings account. Using budgets is great, but not a lot of people can create and adhere to them.
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A company is in the business of finding addresses of long lost friends. The company claims to have a 70 % success rate. Suppose
erastova [34]

Answer:

Following are the solution to this question:

Explanation:

In point a:

Consider Binomial ecxperiment for performance probability, p = 0.70.

Therefore, the chance of fail q = 0.30 (1 - 0.70)

N = 9 Sample size

The Binomial likelihood for each success amount could be found using the Excel function BINOMDSIT (x,n,p,0):

\text{Number of Successes}, x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ Probability, P(X=x) \\\\

0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=0)=BINOMDIST(0, 9, 0.70, 0) =0.000020\\\\1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=1)=BINOMDIST(1, 9, 0.70, 0) =0.000413\\\\2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=2)=BINOMDIST(2, 9, 0.70, 0) =0.003858\\\\3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=3)=BINOMDIST(3, 9, 0.70, 0) =0.021004\\\\4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=4)=BINOMDIST(4, 9, 0.70, 0) =0.073514\\\\

5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=5)=BINOMDIST(5, 9, 0.70, 0) =0.171532\\\\6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=6)=BINOMDIST(6, 9, 0.70, 0) =0.266828\\\\7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=7)=BINOMDIST(7, 9, 0.70, 0) =0.266828\\\\8\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=8)=BINOMDIST(8, 9, 0.70, 0) =0.155650\\\\9\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P(X=9)=BINOMDIST(9, 9, 0.70, 0) =0.040354\\\\

To obtain the necessary Histograms, use X values as just an input X range as well as the probability value values as an output Y range in Excel table in attachment please find it.

In point b:

They recognize that its mean and standard variance of its binomial experiment was,  

Mean = n\times p

          = 9 \times 0.70\\\\=6.3\\\\

\sigma =\sqrt{ npq} \\\\

  = \sqrt{9 \times 0.70 \times 0.30} \\\\ =\sqrt{1.89} \\\\ =1.375

The average is 6.3, so the expected number of friends to whom addresses were found is 6.

In point c:

They must establish the value of n in addition to have P(X \geq 2)=0.97  

This assertion of probability is replaceable as:

\to P(X \geq 2) =1-P(X

\to P(X \leq 1 )=(1-0.97)=0.03

It can be found with the Excel Aim Search feature They must therefore apply approximately 5 identities to be 97% confident that two addresses are found at least.

7 0
3 years ago
On December 31, 2020, Flounder Company signed a $1,278,400 note to Culver Bank. The market interest rate at that time was 10%. T
S_A_V [24]

Answer:

All requirements are solved

Explanation:

An amortization schedule is a complete table of periodic loan payments, showing the amount of principal and the amount of interest that comprise each payment until the loan is paid off at the end of its term. Each periodic payment is the same amount in total for each period.

<u>Requirement A</u>

Amount of cash Flounder received from the loan =(1,278,400 x 0.62092) (102,272 x 3.79079)

Amount of cash Flounder received from the loan = 1,181,476    

   

<u>Requirement B</u>

Date           Cash           Interest         Increase in                 Carrying Amount

               Received Revenue     Carrying Amount         of Note

12/31/20                                                                                      1,181,476

12/31/21    102,272         118,148         15,876                       1,197,352

12/31/22   102,272         119,735         17,463                       1,214,815

<u>Requirement C</u>

Loss due to impairment = 1,214,815 - [(767,040 x 0.75131) (102,272 x 2.48685)]          

Loss due to impairment = 384,195    

6 0
4 years ago
Consider the following situations.
xeze [42]

Answer:

A.$600

B.$100

C. 0.1

Explanation:

Money supply equals to Currency held by the public + Bank reserves÷ Desired reserve-deposit ratio

Hence:

a. Deposits equal bank reserves ÷ by the desired reserve-deposit ratio

= $100/0.25

= $400.

Money supply = currency held by the public + deposits

= $200 + $400

= $600.

b. Let X = currency held by the public = bank reserves.

Thus money supply equals X +X÷ by the desired reserve-deposit ratio

500= X + 0.25

500 = 5X

X=$500/5

X = $100

Currency and bank reserves both equal $100.

c.If the money supply equals $1,250 and the public holds $250 in currency, then the bank deposits must equal $1,000($1,250-$250).

If bank reserves are $100, the desired reserve-deposit ratio

=100/1,000

=0.1

8 0
3 years ago
You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. how man
hram777 [196]
Recall that margin of error is given by:

M=z_{\alpha/2}\sqrt{ \frac{p(1-p)}{n}}  \\  \\ \Rightarrow\frac{M^2}{\left(z_{\alpha/2}\right)^2}= \frac{p(1-p)}{n} \\  \\ \Rightarrow n= \frac{\left(z_{\alpha/2}\right)^2p(1-p)}{M^2}

Given that <span>you want to be 95​% confident that the sample percentage is within 2.5 percentage points of the true population percentage.

This means that z_{\alpha/2}=1.96 and M = 2.5% = 0.025.

Part A:

When nothing is known about the percentage of persengers who prefer aisle seat, we make use of p = 50% = 0.5.

Thus,

n=\frac{1.96^2\times0.5\times0.5}{(0.025)^2}= \frac{0.9604}{0.000625} =1,537

Therefore, 1,537 </span><span>randomly selected air passengers must be​ surveyed to </span><span>be 95​% confident that the sample percentage is within 2.5 percentage points of the true population percentage.



Part B:

Given that recent surveys surgest that about 38% of all air passengers</span> prefer an aisle seat, thus p = 38% = 0.38

<span>Thus,

n=\frac{1.96^2\times0.38\times0.62}{(0.025)^2}= \frac{0.9051}{0.000625} =1,449

Therefore, 1,449 </span>randomly selected air passengers must be​ surveyed to <span>be 95​% confident that the sample percentage is within 2.5 percentage points of the true population percentage.</span>
6 0
4 years ago
On January 1, 2021, Legion Company sold $290,000 of 6% ten-year bonds. Interest is payable semiannually on June 30 and December
stira [4]

Answer:

the bond interest expense for the six months ended June 30, 2021, in the amount of $10,8864

Explanation:

The computation of the interest expense is shown below

= Carrying Value of Bond × Effective interest rate

= $217,719 × 10% yield interest × 6 months ÷ 12 months

= $10,886

Hence, the bond interest expense for the six months ended June 30, 2021, in the amount of $10,8864

Therefore the second option is correct

6 0
3 years ago
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