F(x) = x²-81
g(x) = (x-9) -1(x+9)
= (x-9) -x-9
g(x) • f(x)
= [x²-81 ] • [ (x-9) -x-9 ]
=[ x²-81 ] • [ (x-x -9-9) ]
= [ x²-81 ] •[0-18]
= [ x²-81] •[ -18]
= -18•x² +-81•-18
= -18x²+1458
The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
<h3>What is the value of sin (π/2)?</h3>
The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.
Suppose the value of this function is <em>x</em>. Thus,

Solve it further,
......1
The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

Put this value in the equation 1,

Thus, the range will be,

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
Learn more about the sine values here;
brainly.com/question/10711389
Answer: the lower left data set matches the line plot, or the one with the most values
Answer:
x= 3 over 10 =0.300
Step-by-step explanation:
Hope this helps!