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lutik1710 [3]
3 years ago
14

If p∥q, m∠2=5b+1, and m∠12=6b−8, find m∠1 and m∠3.

Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

jj

Step-by-step explanation:

32

52

jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

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Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below.
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Answer:

Radius length: √5

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Step-by-step explanation:

First we will determine the radius;

Center: (-4, 0)

Point on Circumference: (-2, 1)

d = √(-2 - (-4))^2 + (1 - 0)^2 = √(2)^2 + (1)^2

= √4 + 1 = √5

Therefore the radius is of length √5

Now the equation of a circle is in the form ((x - h)^2 + (y - k)^2) = r^2. The center is in the form (h,k) and r is the radius. Given this our equation would be (x - (-4))^2 + (y - 0)^2 = (√5)^2, or [simplified] (x + 4)^2 + y^2 = 5.

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3 years ago
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vodomira [7]

Answer:

2

Step-by-step explanation:


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4 years ago
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artcher [175]
I believe it’s D not sure though I’m sorry
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2 years ago
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Need some help with this question, any help is appreciated!
Xelga [282]

Answer:

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Step-by-step explanation:

According to the graph we can see that the points where both lines crosses are:

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6 0
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Answer:

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Step-by-step explanation:

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