Answer:
(a) Margin of error ( E) = $2,000 , n = 54
(b) Margin of error ( E) = $1,000 , n = 216
(c) Margin of error ( E) = $500 , n= 864
Step-by-step explanation:
Given -
Standard deviation
= $7,500
= 1 - confidence interval = 1 - .95 = .05
=
= 1.96
let sample size is n
(a) Margin of error ( E) = $2,000
Margin of error ( E) = 
E = 
Squaring both side


n = 54.0225
n = 54 ( approximately)
(b) Margin of error ( E) = $1,000
E = 
1000 = 
Squaring both side


n = 216
(c) Margin of error ( E) = $500
E = 
500 = 
Squaring both side


n = 864
The answer s=16 answer 48
Answer:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Answer:
1.y=x-4
2.y=−2x+5
Step-by-step explanation:
Answer:
From the chapter Playing with numbers
we can define derek has 2×10^2 + 7 × 10^1 + 7× +0^0
as If ABC a number then ABC can be written as 10^2A+10^1B+10^0C
Hope it helps