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3 years ago

I need help 9th grade math

Mathematics

1 answer:

Drupady [299]3 years ago

4 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The equations are :

$- 8 x + 4y = - 2$

$4x - 2y = 1$

The given pair of equations have infinitely many solutions.

(because the first equation is the product of second equation with -2)

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3 years ago

Which of the following can be a Pythagorean triplets?:

PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

$\sf \: {2}^{2} + {2}^{2} = {4}^{2}$

$\sf \: 4 + 4 = 16$

8 ≠ 16

<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

$\sf \:5 {}^{2} + {12}^{2} = {13}^{2}$

$\sf \: 25 + 144 = 169$

169 = 169

<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

$\sf {3}^{2} + {5}^{2} = {6}^{2}$

$\sf 9 + 25 = 36$

34 ≠ 36

<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

$\sf {5}^{2} + {4}^{2} = {7}^{2}$

$\sf \: 25 + 16 = 49$

41 ≠ 49

<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

Only B can be Pythagoras triplet.

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3 years ago