See the attached image for the graph. Specifically figure 2 is the graph you want. You can leave the red points on the graph or decide to erase them (leave behind the blue line though).
To generate each of the red points, you'll plug in various x values to get corresponding y values.
For instance, plug in x = 0 and we get...
y = -|x-6| - 6
y = -|0-6| - 6
y = -|-6| - 6
y = -6 - 6
y = -12
So when x = 0, the y value is -12. The x and y value pair up to get (x,y) = (0,-12)
Another example: plug in x = 2
y = -|x-6| - 6
y = -|2-6| - 6
y = -|-4| - 6
y = -4 - 6
y = -10
So the point (2,-10) is on the graph
The idea is to generate as many points as possible so we get an idea of what this thing looks like.
Generate enough points, and you'll get what you see in Figure 1 (see attached image)
Then draw a line through all of the points. The more points you use, the more accurate the drawing. Doing that will generate the blue function curve you see in Figure 2 (also attached)
Answer:
4.6
Step-by-step explanation:
The answer is 4.6%, hope it helps! sorry if wrong!
The answer is b. All numbers are natural numbers
Answer:
Step-by-step explanation:
The average scores s (on a 100 point scale) for the students can be modeled by
s = 75 - 6 In(t + 1), 0 < t < 12
where t is the time in months.
a) Since the students were given an exam and then retested monthly with equivalent exams, then,
For the original exam, t = 0
Therefore,
s = 75 - 6 In(0 + 1) = 75 - 6 In1
s = 75 - 6 × 0 = 75
b) the average score after 4 months, t = 4
Therefore,
s = 75 - 6 In(4 + 1) = 75 - 6 In5
s = 75 - 9.66 = 65.34
c) s = 60
Therefore,
60 = 75 - 6 In(t + 1)
6 In(t + 1) = 75 - 60 = 15
In(t + 1) = 15/6 = 2.5
t + 1 = e^2.5 = 12.18
t = 12.18 - 1 = 11.18
t = 11 approximately
We need to simplify

First lets factor


=


by applying the radical rule
![\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bab%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%5Csqrt%5Bn%5D%7Bb%7D%20)

By applying the radical rule
![\sqrt[n]{x^m} = x^{m/n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%3D%20x%5E%7Bm%2Fn%7D)
So

=

=

Now let's factor

By applying the radical rule
![\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bab%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%20%5Csqrt%5Bn%5D%7Bb%7D%20)
,

So

=

So

=

We know that
![\sqrt[n]{x} = x^{1/n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B1%2Fn%7D)
so

We now have
We know that
So

We now got

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:

All in All, we get

=

Hope this helps! :D