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Makovka662 [10]
3 years ago
10

There are 40 markers in a bag. Of the 10 scented markers, 6 are permanent markers. Half of the unscented markers are erasable.

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0
For this case we have:
 10 scented markers: Column 1, row 3.
 6 are permanent markers: Column 1, row 1
 Half of the unscented markers are erasable: (1/2) * 30 = 15 Column 2, row 2.
 Therefore, the selected table corresponds to the attached image.
 Answer:
 
See attached image.

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Write 9 as a power of the base 3
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9 = 3^2
Since 3 squared equals 9, that is how 9 as a power of the base 3 should be written. 
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If we wanted to prove quadrilateral MNOP was a parallelogram, which method below would not work?
rjkz [21]

Answer:

The correct option is 4.

4) Doing two distance formulas to show that adjacent sides are not the same length.

Step-by-step explanation:

Parallelogram is a quadrilateral which has opposite sides equals and parallel. Example of a parallelogram are rhombus, rectangle, square etc.

We can prove that a quadrilateral MNOP is a parallelogram. If we find the slopes of all four sides and compare those of the opposite ends, same slopes would indicate the opposite sides are parallel, hence the quarilateral is a parallelogram. We can also find the distance of two opposing sides, and slopes of twp opposing sides to determine whether it is a parallelogram or not. The most difficult approach is that diagonals bisect each other at same point.

However, using only two distance formulas will not give us enough information to determine whether a side is parallel or not.

7 0
3 years ago
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

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Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

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3 years ago
I need help please ASAP !
Natasha2012 [34]

Answer:

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Step-by-step explanation:

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