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kap26 [50]
2 years ago
12

A repair service charges $55.00 to come to your home plus $24.50 per hour. Find a function that describes the arithmetic sequenc

e. Then find the total cost for a 7-hour job.
Mathematics
1 answer:
Kryger [21]2 years ago
5 0

Answer:

f(x)=24.50x+55

Total cost for 7 hours: $226.5

Step-by-step explanation:

We consider that x is the amount of hours.

24.5*7+55=226.5

171.5+55=226.5

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Solve for x<br> -18 = 9 - 3x
iVinArrow [24]

Answer:

3x=9+18

=27

x =27÷3

x=9

the answer of x is 9

6 0
2 years ago
Read 2 more answers
To calculate the cost of painting his silo, a farmer must find its height. The farmer uses a cardboard square to line up the top
tankabanditka [31]

Answer:

Height of the silo = 18 feet.

Step-by-step explanation:

From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.

Farmer is standing at 8 ft distance from the silo.

From triangle AEC,

tan(∠CAE) = \frac{CE}{AE}

                 = \frac{5}{8}

m(∠CAE) = tan^{-1}(\frac{5}{8})

               = 32°

m∠BAE = 90° - 32° = 58°

From the triangle ABE,

tan58° = \frac{BE}{AE}

BE = 8tan58°

BE = 12.8 ft

Total height of the silo = BE + EC

                                         = 12.8 + 5

                                         = 17.8

                                         ≈ 18 ft          

Therefore, total height of the silo is 18 ft.

3 0
3 years ago
The perimeter of a playing field for a certain sport is 334ft. The field is a rectangle, and the length is 47 ft longer than the
babunello [35]

Answer:

The dimensions of the rectangle = 60ft by 107ft

Where 60 ft = Width of the playing field

107ft = Length of the playing field

Step-by-step explanation:

A playing field is Rectangular is shape, hence,

The formula for Perimeter of a rectangle = 2(L + W)

P = 334 ft

L = 47 + W

W = W

Hence we input these values in the formula and we have:

334 = 2(47 + W + W)

334 = 2(47 + 2W)

334 = 94 + 4W

334 - 94 = 4W

240 = 4W

W = 240/4

W = 60

There fore, the width of this playing field = 60 ft

The length of this rectangle is calculated as:

47 + W

47 + 60

= 107 ft

The length of this playing field = 107ft

Therefore the dimensions of the rectangle = 60ft by 107ft

6 0
2 years ago
A laptop producing company also produces laptop batteries, and claims that the batteries
gregori [183]

Answer:

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours. (P-value = 0).

The null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

Step-by-step explanation:

<em>The question is incomplete: To test this claim a sample or population standard deviation is needed.</em>

<em>We will estimate that the sample standard deviation is 2 hours, and use a t-test to test that claim.</em>

<em> NOTE (after solving): The difference between the sample mean and the mean of the null hypothesis is big enough to reject the null hypothesis, even when we have a sample standard deviation of 3.5 hours, which can be considered bigger than the maximum standard deviation for the sample.</em>

This is a hypothesis test for the population mean.

The claim is that the batteries power the laptops for significantly less than 4 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

The significance level is 0.05.

The sample has a size n=500.

The sample mean is M=3.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{500}}=0.0894

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{3.5-4}{0.0894}=\dfrac{-0.5}{0.0894}=-5.5902

The degrees of freedom for this sample size are:

df=n-1=500-1=499

This test is a left-tailed test, with 499 degrees of freedom and t=-5.5902, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours.

5 0
3 years ago
Conic Sections - Part 1
asambeis [7]

Answer:

Step-by-step explanation:

7 0
2 years ago
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