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wariber [46]
3 years ago
5

-2x-3y=48 and -x+2y=-11

Mathematics
2 answers:
Effectus [21]3 years ago
6 0

Answer:

1) y = -2/3x - 16

2) y = 1/2x - 11/2

Step-by-step explanation:

I hope this helps!

melomori [17]3 years ago
3 0

Answer:

first one is y= -2/3x-16

second one is 1/2x-5.5

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What is 1 6/9 +5 9/7
lisabon 2012 [21]

\longrightarrow{\green{7  \frac{20}{21}}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

1 \frac{6}{9}  + 5  \frac{9}{7}  \\   \\ =  \frac{15}{9}  +  \frac{44}{7}  \\  \\  =  \frac{15 \times 7}{9 \times 7}  +  \frac{44 \times 9}{7 \times 9}  \\  \\  =  \frac{105 + 396}{63}  \\  \\  =   \frac{501}{63}  \\  \\  =  \frac{167}{21}  \\  \\  = 7  \frac{20}{21}

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What is the common ratio for this geometric sequence?
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Find the perimeter of the square shown below:<br> Area =49 cm2
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Answer:

28 cm

Step-by-step explanation:

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Order the lengths from least to greatest. 15 in., 14.8 in., 15.8 in., 14.5 in., 15.3 in.​
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Read 2 more answers
Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculato
Mariulka [41]

The mean of the dataset is the average, while the median is the middle element.

  • <em>The mean and the median of the given dataset is 98.2</em>
  • <em>The results support the common belief that the mean body temperature is 98.6F</em>

<em />

The mean of the dataset is calculated using:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{99.2+ 99.2 +98.2+............+97.7}{48}

\bar x = \frac{4715}{48}

\bar x = 98.2

The median position is:

Median = \frac{1}{2}(n + 1)

Median = \frac{1}{2}(48 + 1)

Median = \frac{1}{2}(49)

Median = 24.5

This means that the median is the average of the 24th and 25th element

Using the sorted dataset, we have:

Median = \frac{1}{2}(98.2 + 98.2)

Median = 98.2

<em>Because the calculated mean and the common belief (98.6) are close, then we can conclude that the results support the common belief that the mean body temperature is 98.6F</em>

<em />

Read more about mean and median at:

brainly.com/question/17060266

7 0
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