Answer:
And we can find this probability on this way:
We expect around 68.27% between the two scores provided.
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability on this way:
We expect around 68.27% between the two scores provided.
The small number is 2 the large number is 11.
4(2)+11(3)=41
2(2)+11=15
11(10) -2(6) = 98
hope that helps
Answer:
14.86
Step-by-step explanation:
4.5+ 3.8+ 3.2 +2.3=16.7 divided by 5 which I got from how many numbers I added =14.86
EQUATION 1) 2x - 3y = -4
EQUATION 2) 7x + 9y =- 5
Multiply the whole first equation by 3 so that we could find the values of X first.
1) 3(2x - 3y = -4)
1) 6x-9y=-12
2) 7x+9y=-5
Add the 2 equations together.
13x=-17
x=-17/3 OR -5 2/3
2x-3y=-4
Plug the value of X into the equation.
2(-17/3) -3y=-4
-11 1/3 - 3y=-4
-3y=-4+11 1/3
-3y=22/3
y=-22/9 OR -2 4/9
~Hope I helped!~