1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2
Answer:
0.053246
Step-by-step explanation:
log(26)−log(23)
=1.414973−log(23)
=1.414973−1.361728
=0.053246
Try them step by step
2/3=3/2? No
3/5=12/20? Lets try and see
If we <span>simplify 12/20 what do we do? Well we take 4*3=12 and 4*5=20
Now that we simply the 4 from both the numerator and denominator we get our answer 3/5
Your answer will be B.</span>
Answer:
Step-by-step explanation:Given Equation of line has slope m=-3/2
So the line passing through (4,6) has the same slope because both are parallel
From slope intercept form we have
y-y1=m(x-x1)
y-6=-3/2(x-4)
y-6=-3/2x +3/2(4)
y=-3/2x+12
2y=-3x+24
Since sides kl and kj are congruent that means that angles klj and kjl are congruent. if angle klj is 58 then that means kjl is also 58. so you take the total number of degrees in a triangle (180) and subtract 58 and 58 (116) which leaves you with 64 ( the degree measure of lkj)
cups of flour. Does she have enough flour to bake the bread? Explain how she can compare the fractions to know for sure.