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mash [69]
3 years ago
15

Condense: log26-log23=

Mathematics
1 answer:
Lerok [7]3 years ago
6 0

Answer:

0.053246

Step-by-step explanation:

log(26)−log(23)

=1.414973−log(23)

=1.414973−1.361728

=0.053246

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Solve for x and y by elimination 3x+y=-1
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we need 2 equations to solve by elimination

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(1 point) A tank contains 2640 L of pure water. A solution that contains 0.09 kg of sugar per liter enters the tank at the rate
OverLord2011 [107]

Answer:

t=0      Sugar = 0 Kg

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Step-by-step explanation:

Data

Tank = 2640 L (pure water)

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Sugar in the beginning = ?

if beginning is t = 0min Amount of sugar = 0, this is due to the fact that at the moment of entering the tank the content is only water , but if beginning is t= 1min then;

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7 0
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Z=a/b+c/d solve for A
PilotLPTM [1.2K]

Answer: a=\frac{b(zd-c)}{d}

Step-by-step explanation:

Having the following equation given in the exercise:

z=\frac{a}{b}+\frac{c}{d}

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract \frac{c}{d} from both sides of the equation:

z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

\frac{zd-c}{d}=\frac{a}{b}

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}

6 0
3 years ago
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