A car is initially sliding backwards down a hill at -25 km/h. The driver guns the car. By the time the car's velocity is +35 km/
1 answer:
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Answer:
t = 12 s
Explanation:
To find the time in which the police reaches the thief you write the equation of motion of both thief and police:
The thief has a constant velocity, the position is then given by:
(1)
The police has an acceleration, then the position is:
(2)
the time in which the police reaches the thief is when their positions are equal, that is, when expression (1) equals expression (2). But before you calculate the acceleration of the police:
you replace this values in (2) and you equal the expression (1) and (2) (with vo = 0):
one root is t = 0s, but it is omitted because is the momment in which the thief pass in front of the police. The other root is:
hence, the time is 12 s
Answer: The time of contact will be 0.006 seconds.
Explanation:
An impulse of a force is the product of average force and the time interval when the force acts.
Mathematically,
Where,
J = impulse = 3.6 Ns
F = Force = 600N
= Time = ?s
Putting the values in above equation, we get:
t = 0.006 seconds
Hence, the time of contact will be 0.006 seconds.