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Fiesta28 [93]
3 years ago
12

What are the three longest wavelengths for standing sound waves in a 121-cm-long tube that is (a) open at both ends and (b) open

at one end, closed at the other?
Physics
1 answer:
irina [24]3 years ago
3 0

Answer:A)For open pipe

1stπ=484cm

2nd wavelength=161.3cm

3rd is=96.8cm

B)For closed pipe

1st wavelength=242cm

2nd=121cm

3rd wavelength=80.7cm

Explanation:

An open pipe produces a standing waves whose wavelength is related to it's length(length of pipe) by nL/4=π ,where n represent odd integers 1,2,3...

So the first note called fundamental note or 1st Harmonic is L=π/ 4,121=π/ 4

π= 121×4=484cm

Third harmonic,L=3π /4

So π= 4l/3=4×121/3=161.3cm

The 3rd wavelength is

Fifth harmonic=

π =4l/5=4×121/5=96.8cm

For a pipe open at one end and closed at the other also called closed pipe

Fundamental note is

2L/n= π where n=1,2,3....ie integers

First wavelength

π=2L=2×121=242cm

Second wavelength

π=L=121cm

Third is

π=2L/3=2×121/3=80.7cm

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Answer:

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         The charge on the particle is q = 1.22*10^{-8}C

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The charge experienced  a force which is mathematically represented as

         

                    F = q (\= v * \= B)

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         F = 1.22*10^{-8} (( 3*10^4 ) \r j \ \ X \ \  ( 1.63 \r i  + 0.980 \r j )T)

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           i \ \ X \ \ j = k \\\\j \ \  X  \ \ k = i\\\\k  \ \ X \ \ i = j\\\\j \ \ X \ \ i = -k \\\\k \ \  X  \ \ j = -i\\\\i  \ \ X \ \ k = - j\\

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Answer:

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verified

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(a) The labelled diagram is shown.

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