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Fiesta28 [93]
3 years ago
12

What are the three longest wavelengths for standing sound waves in a 121-cm-long tube that is (a) open at both ends and (b) open

at one end, closed at the other?
Physics
1 answer:
irina [24]3 years ago
3 0

Answer:A)For open pipe

1stπ=484cm

2nd wavelength=161.3cm

3rd is=96.8cm

B)For closed pipe

1st wavelength=242cm

2nd=121cm

3rd wavelength=80.7cm

Explanation:

An open pipe produces a standing waves whose wavelength is related to it's length(length of pipe) by nL/4=π ,where n represent odd integers 1,2,3...

So the first note called fundamental note or 1st Harmonic is L=π/ 4,121=π/ 4

π= 121×4=484cm

Third harmonic,L=3π /4

So π= 4l/3=4×121/3=161.3cm

The 3rd wavelength is

Fifth harmonic=

π =4l/5=4×121/5=96.8cm

For a pipe open at one end and closed at the other also called closed pipe

Fundamental note is

2L/n= π where n=1,2,3....ie integers

First wavelength

π=2L=2×121=242cm

Second wavelength

π=L=121cm

Third is

π=2L/3=2×121/3=80.7cm

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The tin can in the story is a lot like our bodies. As long as it has air inside and air outside, the pressure is the same in both directions, so there's no particular force trying to deform the can. But ...

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