Answer:
Transcription and Translation. I hope this helps!
After the foot leaves the ball, the acceleration is always downward and is equal to g at all points
A. At the top. At this point, the child is highest, and they are not moving. Their potential energy is much greater.
Answer:
Explanation:
s = 50 t^2
Differentiate both sides with respect to t
ds/dt = 50 x 2 t
ds/dt = 100 t
Substitute t = 10 second
ds/dt = 100 x 10
ds/dt = 1000 m/s
thus, the rate of change of elevation is 1000 m/s.
Work = (force) x (distance)
Power = (work) / (time)
Knowing force, distance, and time, it looks like
you can calculate both <em>work and power</em>.
But that's not all !
-- <u>Speed</u> = (distance) / (time)
-- <u>Impulse</u> = change in momentum = (force) x (time)
