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fenix001 [56]
3 years ago
12

3x 2 + 2x - 5 and -4 + 7x 2

Mathematics
2 answers:
fiasKO [112]3 years ago
4 0

Answer:

16+2x-5adn

Step-by-step explanation:

6+2x-5adn-4+14. solution: is 16=2x-5adn

vladimir1956 [14]3 years ago
4 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{10 {x}^{2}  + 2x - 9}}}}}

Step-by-step explanation:

\sf{3 {x}^{2}  + 2x - 5 + ( - 4 + 7 {x}^{2} )}

When there is a ( + ) in front of an expression in parentheses, there is no need to change the sign of each term.

That means , the expression remains the same.

⇒\sf{3 {x}^{2}  + 2x - 5 - 4 + 7 {x}^{2} }

Collect like terms

⇒\sf{ {10x}^{2}  + 2x - 5 - 4}

Calculate

⇒\sf{10 {x}^{2}  + 2x - 9}

Hope I helped!

Best regards!!

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Read 2 more answers
Plz guys help i need asap<br> its part b im stuck
aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

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2 years ago
Use Newton's method to approximate a root of the equation 3x^7+2x^4+3=0 Let x1 =1 be the initial approximation. The second appro
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Answer:

3.3

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2 years ago
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