Consider the titration of 30.0 mL of 0.200 M HClO4 with 0.100 M KOH. Calculate the pH of the resulting solution after the follow
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The product of the reaction of excess benzene with dichloromethane is diphenylmethane.
The reaction that benzene undergoes with dichloromethane is a Friedel-Crafts Alkylation, in which firstly Benzene is alkylated to Benzyl Chloride, and after that, the Benzyl Chloride reacts with another equivalent of Benzene to form the compound Diphenylmethane. The Reaction Scheme is shown in the image below:
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The product of the reaction of excess benzene with dichloromethane is diphenylmethane.
The reaction that benzene undergoes with dichloromethane is a Friedel-Crafts Alkylation, in which firstly Benzene is alkylated to Benzyl Chloride, and after that, the Benzyl Chloride reacts with another equivalent of Benzene to form the compound Diphenylmethane. The Reaction Scheme is shown in the image below:
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