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soldier1979 [14.2K]
1 year ago
13

What is the freezing point of an aqueous suger (C12H22O11) solution that boils at 110C°?

Chemistry
1 answer:
AURORKA [14]1 year ago
7 0

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

<h3>What is the freezing point?</h3>

The temperature at which a liquid solidifies.

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

Learn more about the freezing point here:

brainly.com/question/3543605

#SPJ1

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Explanation:

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An endergonic reaction with a Δh and Δs can be changed into an exergonic reaction.
zheka24 [161]

Full question:

This question is incomplete, here it is completed:

An endergonic reaction with a ______ ∆H and a ______ ∆S can be changed into an exergonic reaction by decreasing the temperature.

Option A: negative, positive

Option B: negative, negative

Option C: positive, positive

Option D: positive, negative

Answer:

Option B: negative, negative

Explanation:

The change in free energy (ΔG) of a system for a constant-temperature process is

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Looking at the equation, we can see that if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS  is smaller in magnitude than ΔH. This condition is met when T is small.

ΔG = ΔH - TΔS

           -        -

This means that the reaction proceeds spontaneously at low temperatures. At high temperatures, the reverse reaction becomes spontaneous. An example of that would be the following reaction:

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Answer:

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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From the balanced equation above,

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The mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This include:

Volume of acid, HCl (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Concentration of base, NaOH (Cb) = 0.1020 M

Concentration of acid, HCl (Ca) =?

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Ca × 25 / 0.1020 × 34.55 = 1/1

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Cross multiply

Ca × 25 = 3.5241 × 1

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