Answer:
The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)
Explanation:
Step 1: Data given
Initial temperature = 10.0 °C
Final temperature = 25.0 °C
Energy required = 30000 J
Mass of the object = 40.0 grams
Step 2: Calculate the specific heat capacity of the object
Q = m* c * ΔT
⇒With Q = the heat required = 30000 J
⇒with m = the mass of the object = 40.0 grams
⇒with c = the specific heat capacity of the object = TO BE DETERMINED
⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C
30000 J = 40.0 g * c * 15.0 °C
c = 30000 J / (40.0 g * 15.0 °C)
c = 50 J/g°C
The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)
It’s one... electron affinity
Answer:
52.5 mol O2
Explanation:
4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2
4 mol FeCl3 -> 6 mol O2
35.0 mol FeCl3 -> x
x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3
x=52.5 mol O2
Weathering and chemical substance weathering
