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Marina86 [1]
2 years ago
10

A mixture of 10cm3 of o2 and 50 cm3 of hydrogen gas sparked together to form water calculate volume of non limiting reagent left

after reacton completion
Chemistry
1 answer:
Firdavs [7]2 years ago
6 0

Answer:

30 cm³.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

O2 + 2H2 —> 2H2O

From the balanced equation above, we can say that:

1 cm³ of O2 reacted with 2 cm³ of H2 to produce 2 cm³ of H2O.

Next, we shall determine the excess reactant.

This can be obtained as follow:

From the balanced equation above,

1 cm³ of O2 reacted with 2 cm³ of H2.

Therefore, 10 cm³ of O2 will react with = (10 × 2)/1 = 10 × 2 = 20 cm³ of H2.

From the calculations made above, we can see that only 20 cm³ out of 50 cm³ of H2 given is needed to react completely with 10 cm³ of O2.

Therefore, O2 is the limiting reactant and H2 is the excess reactant (non limiting reactant).

Finally, we shall determine the volume of the non limiting reactant (excess react) that is remaining after the reaction.

This can be obtained as follow:

Volume of non limiting reactant (H2) = 50 cm³

Volume of non limiting reactant (H2) that reacted = 20 cm³

Volume of non limiting reactant (H2) remaining =.?

Volume of non limiting reactant (H2) remaining = (Volume of non limiting reactant) – (Volume of non limiting reactant that reacted)

Volume of non limiting reactant (H2) remaining = 50 – 20

= 30 cm³

Therefore, the Volume of non limiting reactant (H2) that remains after the reaction is 30 cm³

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The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

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1 year ago
What equipment might you use to find the SHC of a material? Need to know the answer ASAP PLZ
algol [13]
Theses can include the power supply circuit a joule meter to measure the energy transferred which makes the calculations a lot easier.
4 0
3 years ago
Write the ionization equation for hypochlorous acid, HClO, dissolved in water.
Pavel [41]

Answer:

HClO (l)  →  H⁺ (aq)    +       ClO⁻ (aq)

                 proton   and    hypochlorite.

Explanation:

HClO (Hypochlorous acid)

This is a weak acid that can be dissociated as this:

HClO (l)  →  H⁺ (aq)    +       ClO⁻ (aq)

                 proton   and    hypochlorite.

It is a weak acid, so it can adopt a Ka for its equilibrium

HClO +  H₂O  ⇄   H₃O⁺   +  ClO⁻          Ka

Molar mass = 52.46 g/m

5 0
3 years ago
It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0?C to 24.3?C. What is the specific heat for
svet-max [94.6K]

Answer:

c = 0.377 J/g.°C

c = 0.2350 J/g.°C

J = 27.3 J

Explanation:

We can calculate the heat (Q) absorbed or released by a substance using the following expression.

Q = c × m × ΔT

where,

c: specific heat

m: mass

ΔT: change in the temperature

<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>

Q = c × m × ΔT

49.0 J = c × 11.5 g × (24.3°C - 13.0°C)

c = 0.377 J/g.°C

<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>

<em />

The molar mass of silver is 107.87 g/mol. The specific heat of silver is:

\frac{25.35J}{mol.\° C} .\frac{mol}{107.87g} =0.2350J/g.\° C

Q = c × m × ΔT

Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J

5 0
3 years ago
Convert .004569g to mg
algol [13]

Answer:

4.569 mg

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4 0
3 years ago
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