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Alborosie
3 years ago
11

Help me with this question

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0
The answer is 10%, 0.1 or 1/10, depending on the format. 15 students out of 150 in the school both like pudding and dislike anime. 15/150= 0.1

In case you were wondering if the group/divisor was the 65 students who dislike anime, the phrasing of the question says the total amount of students.
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Attachment look at it​
stiks02 [169]
4J-7S
21/7=3

multiply both sides by 3
12J-21S
12 cups of juice to make 21 cups of soda
4 0
3 years ago
Find a polynomial, which, when added to the polynomial 5x^2–3x–9, is equivalent to:
djyliett [7]
So you need to turn 5x^2 -3x -9 into 2x - 3. 

Well first you need  to take 5x^2 out by subtracting 5x^2 (-5x^2). 

Then -3x needs to become 2x by adding 5x (+5x). 

Finally -9 needs to become -3 by adding 6 (+6).

Put all the things you did together to make a polynomial.
-5x^2 + 5x + 6
8 0
3 years ago
How do I solve this algebra two btw
pychu [463]

\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}

now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then

\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill

7 0
3 years ago
An archer hits the center of the target (the bullseye) 70 percent of the time. However, she is a streak shooter, and if she hits
laiz [17]

Answer:

0.595

Step-by-step explanation:

We are given that An archer hits  centre of the target

We have to calculate the probability that she will hit the centre of the target on two consecutive shots.

P(A)=P(B)=0.70

P(B/A)=0.85

We know tha formula

P(B/A)=\frac{P(A\cap B)}{P(A)}

Substitute the value then we get

P(A\cap B)=P(B/A)\cdot P(A)=0.85\times 0.70=0.595

Hence, the probability that she will hit the centre of the target on two consecutive shots=0.595

3 0
3 years ago
Find the probability P(E or F) if E and F are mutually exclusive, P(E)=0.41 and P(F) = 0.47
statuscvo [17]

Answer:

P(E or F)=P(E)+P(F)=0.41+0.47=0.88

4 0
3 years ago
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