<u>Answer:</u> The expression of
is written below.
<u>Explanation:</u>
We are given a chemical compound which is trimethylamine that acts as a weak base when dissolved in water.
It accepts a proton from the water to form trimethylammonium ion and hydroxide ion.
The chemical equation for the reaction of trimethylamine in water follows:

The expression of
for above equation follows:
![K_b=\frac{[(CH_3)_3NH^+][OH^-]}{[(CH_3)_3N]}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%7B%5B%28CH_3%29_3NH%5E%2B%5D%5BOH%5E-%5D%7D%7B%5B%28CH_3%29_3N%5D%7D)
Hence, the expression of
is written above.
Answer : The number of sodium ions is equal to the number of formula units of salt.
Explanation : In the given reaction of NaCl the statement which describes it the best is that the number of sodium ions is found to be same along with the formula units in the product side.
+
----> NaCl.
Its clear from the equation that one mole of Na and one mole of Cl combines together to give the product, which is one mole of NaCl. The number of ions on both the sides are equal.
Answer:
You multiply the 3 numbers together to get your volume, in this case it would be 4058.488 cm^3 (cm cubed)
so
V: 4058.488cm^3 ( round up to 4058.5 for convenience)
M: 27579
D: ?
So we divide mass by the volume to get density, which is
27579 / 4058.5 = ~6.79536 (can round up to 7 or 6.8)
This graph can help a lot, so maybe try and memorize it, hope I helped.
Hello there.
<span>A 250.0 ml buffer solution is 0.250 M in acetic acid and. 250M in sodium acetate. what is the ph after addition of. 0050 mol of HCL? what is the ph after the addition of. 0050 mol of NaOH?
Part 2 answer: </span><span>pH = 4.67 </span>