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Anton [14]
2 years ago
12

¿Cuántos moles hay en 350 g de NaNO3?

Chemistry
1 answer:
olga55 [171]2 years ago
4 0

Answer:

3 moles

Explanation:

So, approximately 3 moles of NaNO3 can be obtained, by reacting 253 grams of Na2CrO4. Also, the number of moles is a dimensionless quantity.

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Which properties make a metal a good material to use for electrical wires? malleability and reactivity conductivity and ductilit
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2 years ago
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Calculate the cell potential at 25oC under the following nonstandard conditions: 2MnO4-(aq) + 3Cu(s) + 8H+(aq) ⟶ 2MnO2(s) + 3Cu2
baherus [9]

Answer:

1.346 v

Explanation:

1) Fist of all we need to calculate the standard cell potential, one should look up the reduction potentials for the species envolved:

(oxidation) Cu_{(s)} →Cu^{2+}_{(aq)} +2e E°=0.337 v

(reduction) MnO_{4 (aq)} + 3e + 4H^{+}_{(aq)}→MnO_{2 (aq)}+2H_{2}O E°=1.679 v

(overall) 2MnO_{4 (aq)}+3Cu_{(s)}+8H^{+}_{(aq)}→3Cu^{2+}_{(aq)}+2MnO_{2 (aq)}+4H_{2}O E°=1.342 v

2) Nernst Equation

Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

5 0
2 years ago
In an electron dot diagram what is the maximum number of dot surrounding a symbol. A. 8 B.4 C. 2 D.10
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Answer:

A. 8

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3 years ago
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3 years ago
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Write a report on waves
Bad White [126]

Answer:

The epic emotional journey of a suburban African American family as they navigate love, forgiveness and coming together in the wake of a tragic loss.

Explanation:

hope thsi helps if so please brainliest

Merry Christmas

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