1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolbaska11 [484]
3 years ago
15

A student is curious about the Ksp value for NaCl. The student looks up the value om the appendix of his textbook but cannot fin

d a value for NaCl. Why not?
Chemistry
1 answer:
Leno4ka [110]3 years ago
7 0

Given :

The student looks up the value of the appendix of his textbook but cannot find a value for NaCl.

To Find :

Why the Ksp of NaCl is not present .

Solution :

Ksp values are given for those compounds which are partially soluble or insoluble in water .

But , we know NaCl is strong electrolyte and it completely dissociated in water .

So , the reaction go forward and their is no need to calculate Ksp .

Therefore , the Ksp of NaCl is not present .

Hence , this is the required solution .

You might be interested in
In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
2.38g of black copper(iii) oxide is completely reduced to by hydrogen to give copper and water. What are the number of atoms of
OleMash [197]

Explanation:

here is the answer bae. Feel free to ask for more

6 0
2 years ago
What is the speed of a car that has traveled 100 miles in 20 hours?<br> |
77julia77 [94]

Answer:

5 mph

Explanation:

100 miles, 20 hours (divide by 2)

50 miles,    10 hours (divide by 2)

25 miles,    5 hours (divide by 2)

divide both sides by 5

5 miles,     1 hour

3 0
3 years ago
Read 2 more answers
Why the stability of No+ is greater than No?
lyudmila [28]
Because of the protons connected to the Nitrogen oxide group giving it its positive charge.
7 0
2 years ago
Aluminum is manufactured using electrolysis. Carbon electrodes are used. Describe the nature of the electrolyte.​
Aleksandr [31]

Answer:

The traditional electrolyte for aluminium electrolysis is based on molten cryolite (Na3AlF6), acting as solvent for the raw material, alumina (Al2O3).Metals are found in ores combined with other elements. Electrolysis can be used to extract a more reactive metal from the ore.

Aluminum can and is used as both anodes and cathodes in electrochemical cells, but there are some peculiarities to using it as an anode in aqueous solutions. As you note, aluminum forms a passivating oxide layer quite readily, even by exposure to atmosphere. In an aqueous solution, if the potential is high enough, OH− and O2− are generated at the anode, which can then react with the aluminum to produce aluminum oxide. Al^3+ can also be generated directly. The electric field will draw the anions through the growing aluminum oxide layer towards the aluminum surface and the Al^3+ towards the solution, making the oxide layer grow both away from the electrode surface and into the surface of the electrode. In this way, coatings thicker than the normal passivation in air can be produced. However, aluminum oxide is a good electrical insulator, thus if a dense non-porous layer is grown, it will become impossible to pass current through it and growth will stop, leaving a relatively thin oxide layer (this is how the dielectric layers in electrolytic capacitors are made). This is the normal behaviour in aqueous solutions at near-neutral pH (5–7).

However, if a thick aluminum oxide layer is desired (e.g. to produce coatings on aluminum parts for dying or durability), maintaining porosity is necessary to avoid completely blocking access to the surface. One technique that is commonly used is using a low pH solution, which tends to redissolve some of the oxide and neutralize some of the formed OH−, leaving pores in the oxide layer through which the ions can travel and continue to react. These pores also give a good structure to retain dyes or lubricants, but generally need to be sealed after to protect against corrosion.

3 0
2 years ago
Other questions:
  • Most of earths carbon is in the atmosphere in the form of ___
    8·1 answer
  • In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz,
    8·1 answer
  • Which of the following can be formed by physically combining pure substances? a. an element c. a compound b. a mixture d. all of
    9·1 answer
  • Increasing the temperature increases the vaporization rate of a liquid because the excess energy is used to break covalent bonds
    14·1 answer
  • An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
    9·2 answers
  • Describe a method of Municipal treatment of water with neat diagram?​
    6·1 answer
  • Ammonium sulfate, an important chemical fertilizer, can be prepared by the reaction of ammonia with sulfuric acid according to t
    15·1 answer
  • 11) How many moles of CO2 can be produced from<br> 5.0 moles of O2?
    9·1 answer
  • Write down the ratio of the atom present in the formula for each of the compound. a) Sodium Carbonate , Na2CO3 b) Glucose, C6H12
    5·1 answer
  • Separating mixtures: filtration​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!