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morpeh [17]
3 years ago
13

Which scientist proposed the model of an atom as a nucleus surrounded by electrons?

Chemistry
2 answers:
marusya05 [52]3 years ago
8 0

Answer:

The correct answer will be option-Ernest Rutherford.

Explanation:

Atom is the smallest unit of matter which was earlier thought to be indestructible but later new findings suggested that atom contains sub-atomic particles.  

The arrangements of these sub-atomic particles in an atom were represented by many models, best accepted of which is presented by Ernest Rutherford in 1911.

His experimental findings concluded that a dense heavy nucleus is present in the center of an atom which is surrounded by a negatively charged nucleus.

Thus, the selected option is the correct answer.

bezimeni [28]3 years ago
3 0

The answer is Ernest Rutherford.

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HCl(?) + H2O(?) → H3O+(?) + Cl-(?)
larisa86 [58]

Answer:

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the following question for the mixing of gaseous hydrogen chloride with water to make hydrochloric acid. HCl) + H2O(2) → H30*) + Cl (2) What is the phase label on HCI? aq

6 0
2 years ago
Multiple covalent bonds may occur in atoms that contain carbon,nitrogen, or
Arisa [49]

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8 0
3 years ago
If a container contains 3.5 moles and has a volume of 1.5 L, then what volume is it when it contains 8 moles? *
Lilit [14]
Volume would be 3.4 L
8 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 200-mg sample. (a) Find the mass that remains after t years.
scZoUnD [109]

Given:

Half life(t^ 1/2) :30 years

A0( initial mass of the substance): 200 mg.

Now we know that

A= A0/ [2 ^ (t/√t)]

Where A is the mass that remains after t years.

A0 is the initial mass

t is the time

t^1/2 is the half life

Substituting the given values in the above equation we get

A= [200/ 2^(t/30) ] mg


Thus the mass remaining after t years is [200/ 2^(t/30) ] mg

5 0
3 years ago
Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i
ankoles [38]
First, we need to get the value of Ka:

when Ka = Kw / Kb 

we have Kb = 1.8 x 10^-5 

and Kw = 3.99 x 10^-16  so, by substitution:

Ka = (3.99 x 10^-16) /  (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

                 NH4+  + H2O →NH3 +  H+
intial          0.013                       0         0 

change       -X                          +X      +X

Equ        (0.013-X)                      X         X

when Ka = [NH3][H+] / [NH4+] 

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X)  by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]
 
        = -㏒(5.35 x 10^-7)
        = 6.27
6 0
3 years ago
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