Explanation:
As the Earth moves around the sun during a year, the northern half of the Earth is tilted towards the sun in the summer, making daytime longer than night. In winter, this reverses; the earth tilts away from the sun and nighttime becomes longer
Answer:
the rock layers of the Grand Canyon
Explanation:
Steno's law are laws that applied to sedimentary rocks. These laws helps in understanding sedimentary sequences.
Sedimentary rocks are derived from the deposition of pre-existing rocks in basins. In order to understand some important relationships between these rock layers, Steno's law offer a good insight.
Steno's law are often applied when we want to do relative dating of rock layers. Some of the laws are:
- Law of superposition of strata
- Law of original horizontality
- Law of lateral continuity
- Law of inclusion
- Law of fossil and fauna succession
These laws helps to interpret sedimentary rock sequences better.
Answer:
ΔH = 125.94kJ
Explanation:
It is possible to make algebraic sum of reactions to obtain ΔH of reactions (Hess's law). In the problem:
1. 2W(s) + 3O2(g) → 2WO3(s) ΔH = -1685.4 kJ
2. 2H2(g) + O2(g) → 2H2O(g) ΔH = -477.84 kJ
-1/2 (1):
WO3(s) → W(s) + 3/2O2(g) ΔH = 842.7kJ
3/2 (2):
3H2(g) + 3/2O2(g) → 3H2O(g) ΔH = -716.76kJ
The sum of last both reactions:
WO3(s) + 3H2(g) → W(s) + 3H2O(g)
ΔH = 842.7kJ -716.76kJ
<h3>ΔH = 125.94kJ </h3>
Hello!
The concentration of the final solution when a<span> chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water is
0,3 MTo calculate that, you'll need to use the dilution law, where initial and final concentrations are M1 and M2 respectively, and initial and final volumes are V1 and V2, as shown below.
Keep in mind that the final volume is the sum of the 200 mL of water and the 50 mL of H</span>
₂SO₄ that were added by the teacher. 
Have a nice day!
Answer:
A
Explanation:
the correct answer is A
This is the sidereal month. It is measured against the background stars. However, the Earth is also orbiting the Sun, and the moon needs extra time to catch up to its previous position relative to the Sun.
