Answer:
N≡N bond
Explanation:
Bond energy (bond enthalpy) is a measure of the bond strength in the bond. It is defined as average value of bond dissociation energies in the gas-phase for all the bonds having same type with in same chemical species.
<u>The greater the bond energy, the greater is the amount of energy required to break the bond, the more stable is the bond.</u>
Thus, among the following bonds:
O=O 498 kJ/mol
N≡N 946 kJ/mol
C=C 614 kJ/mol
C=O 745 kJ/mol
C≡C 839 kJ/mol
<u>The greatest bond energy is of N≡N 946 kJ/mol and thats why it is the most stable.</u>
If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If instead, you throw it downward, its downward acceleration after release is 9.8 m/s2.
Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration. Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.
A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific designation is given to the numerical value for an object in free fall because it is such an essential value. The longer an object is in free fall, the faster it descends toward the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.
To know more about acceleration refer to: brainly.com/question/14468548
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Answer:
The statement is not correct.
Reason:
If two objects have the same mass, their respective densities determine their volumes.
By definition,
density = mass/volume.
or volume = mass/density.
Therefore if two objects have the same mass, the mode dense object (with higher density) will occupy less volume than the other object.
Answer:
F = 789 Newton
Explanation:
Given that,
Speed of the car, v = 10 m/s
Radius of circular path, r = 30 m
Mass of the passenger, m = 60 kg
To find :
The normal force exerted by the seat of the car when the it is at the bottom of the depression.
Solution,
Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.
N = 788.6 Newton
N = 789 Newton
So, the normal force exerted by the seat of the car is 789 Newton.
