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creativ13 [48]
2 years ago
10

Based on the bond energies given for each of the following which is the most stable? O=O 498 kJ/mol N≡N 946 kJ/mol C=C 614 kJ/mo

l C=O 745 kJ/mol C≡C 839 kJ/mol
Physics
1 answer:
slamgirl [31]2 years ago
7 0

Answer:

N≡N bond

Explanation:

Bond energy (bond enthalpy) is a measure of the bond strength in the bond. It is defined as average value of bond dissociation energies in the gas-phase for all the bonds having same type with in same chemical species.

<u>The greater the bond energy, the greater is the amount of energy required to break the bond, the more stable is the bond.</u>

Thus, among the following bonds:

O=O 498 kJ/mol

N≡N 946 kJ/mol

C=C 614 kJ/mol

C=O 745 kJ/mol

C≡C 839 kJ/mol

<u>The greatest bond energy is of N≡N 946 kJ/mol and thats why it is the most stable.</u>

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umka2103 [35]

Answer:

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Explanation:

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2 years ago
A 12 kg block is accelerating at the rate of 9.0 m/s? while being acted on by two forces.
Aliun [14]

Answer:

See below

Explanation:

F = ma

F = 12 * 9 = 108 N

  108 N  needed      <u> add  30 N more east </u>

8 0
1 year ago
A 73.9 kg weight-watcher wishes to climb a
Tresset [83]

The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

<h3>How to determine the energy. </h3>

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

<h3>How to determine the height </h3>
  • Energy (E) = 428706.6 J
  • Mass (m) = 73.9 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) =?

E = mgh

Divide both side by mg

h = E / mg

h = 428706.6 / (73.9 × 9.8)

h = 591.95 m

Divide by 1000 to express in km

h = 591.95 / 1000

h = 0.59 Km

Learn more about energy:

brainly.com/question/10703928

7 0
2 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k
Aleks [24]

Answer:

mass of the neutron star =3.45185×10^26 Kg

Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

\frac{GM_{ns}}{R^2}= \omega^2 R

M_ns = mass odf the netron star.

G= gravitational constant = 6.67×10^{-11}

R= radius of the star = 18×10^3 m

ω = 10 rev/sec = 20π rads/sec

therefore,

M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}

= 3.45185... E26 Kg

= 3.45185×10^26 Kg

4 0
3 years ago
Am I correct?? Will give brainliest
Anna35 [415]
Yes that looks correct to me. good luck!!
5 0
3 years ago
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