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creativ13 [48]
3 years ago
10

Based on the bond energies given for each of the following which is the most stable? O=O 498 kJ/mol N≡N 946 kJ/mol C=C 614 kJ/mo

l C=O 745 kJ/mol C≡C 839 kJ/mol
Physics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

N≡N bond

Explanation:

Bond energy (bond enthalpy) is a measure of the bond strength in the bond. It is defined as average value of bond dissociation energies in the gas-phase for all the bonds having same type with in same chemical species.

<u>The greater the bond energy, the greater is the amount of energy required to break the bond, the more stable is the bond.</u>

Thus, among the following bonds:

O=O 498 kJ/mol

N≡N 946 kJ/mol

C=C 614 kJ/mol

C=O 745 kJ/mol

C≡C 839 kJ/mol

<u>The greatest bond energy is of N≡N 946 kJ/mol and thats why it is the most stable.</u>

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Vika [28.1K]

Answer:

v = 8.03 m / s

Explanation:

This is a missile throwing exercise.

          y = y₀ + v_{oy}  t - ½ g t²

     

indicates that y = -1.2 m and the initial velocity is

         v_{oy} = v₀ sin θ

         v_{oy} = 6.4 sin 2.2

         v_{oy} = 0.2457 m / s

we substitute in the equation

         -1.2 = 0.2457 t - ½ 9.8 t²

          4.9 t² - 0.2457 t - 1.2 = 0

          t² - 0.05014 t -0.2449 = 0

we solve the quadratic equation

          t = [0.05014 ±√ (0.05014² + 4 0.2449)] / 2

          t = [0.05014 ± 0.9910] / 2

          t₁ = 0.5206 s

          t₂ = -0.47 s

time must be a positive magnitude therefore the correct answer is

          t = 0.5206 s

with this time we can calculate the vertical speed when the rock hits the ground

         v_{y} = v_{oy} - gt

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the negative sign indicates that the speed is down

horizontal velocity is constant, due to no acceleration

         vₓ = v₀ₓ = v₀ cos 2,2

         v₀ₓ = 6.4 cos 2.2

         v₀ₓ = 6.395 m / s

therefore let's use Pythagoras' theorem to find the velocity

         v = √ (vₓ² + v_{y}^{2})

         v = √ (6,395² + 4,856²)

         v = 8.03 m / s

the direction can be found with trigonometry

        tan θ = v_{y} / vₓ

        θ = tan⁻¹ (-4,856 / 6,395)

        θ = - 37

the negative sign indicates that it is half clockwise from the x axis

   

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3 years ago
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Answer:

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After some algebraic handling, the following expression is found:

-\mu_{k}\cdot m \cdot g = m \cdot a

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a = - (0.2)\cdot (9.807\,\frac{m}{s^{2}} )

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