Answer:
Formula to find the area of a triangle is 1/2(bxh). The area of the right triangle is 28.
Step-by-step explanation:
To solve this problem you would plug in the base and height into the formula and follow the order of operations (P.E.M.D.A.S). So the equation would then read 1/2(5x11.2). Once you solve inside the parenthesis, the equation then reads, 1/2(56). Then you solve what half of 56 is, which is 28.
I hoped this helped you!
First let us find the length of JN
JN =JK +KN
JN = 82+105 = 187
JN=187..............(1)
UC= JN -( JH +HU+CN)
We are given :
JH= 22, HU = 96 and CN = 51
plugging all the values we get
UC = 187-( 22+96+51)
UC =187 -169
UC = 18
Answer is UC =18 ( option B)
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Answer:
2.5
Step-by-step explanation:
you can use pythag theorem and divide c by two:
-3^2+4^2=c^2
9+16= 25
c=5
however, 5/2=2.5
Answer:
$0.34
Step-by-step explanation:
a = p*w
a = .06*5.65
a = 0.339
rounded = 0.34
hope this helps :)