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2 years ago

7

Find the remainder when f(x) is divided by (x - k).

1 answer:

rusak2 [61]2 years ago

6 0

Synthetic division:

3 | 3 11 2 -7 61
. | 9 60 186 537
- - - - - - - - - - - - - - - - - - - -
. | 3 20 62 179 598

which translates to

$\dfrac{3x^4+11x^3+2x^2-7x+61}{x-3}=3x^3+20x^2+62x+179+\dfrac{598}{x-3}$

i.e. you're left with a remainder of 598.

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A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average wo

klemol [59]

Answer: A. $4.3\times10^7$

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately $6.0 \times 10^2$ megabytes of information.

1 megabyte = $10^6$ bytes

Then, The storage capacity of CD-ROM disk will be :

$10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8$

If an average word requires 14 bytes of storage, then the number of words can be stored :-

$\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7$

Hence, number of words can be stored = $4.3\times10^7$

4 0

3 years ago

A ____ is a pair of equal ratios.

12345 [234]

A proportion is a pair of equal ratios.

6 0

2 years ago

jack has 14 cards. by the end of the week his amount of cards has doubled. how many cards does jack have now

slava [35]

Answer:

Jack has 28 cards.

Step-by-step explanation:

To double 14, multiply 14 times 2. 14x2=28

6 0

3 years ago

Read 2 more answers

What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?

DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. $\frac{n(n-3)}{2}$

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

$\frac{n(n-3)}{2}$

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = $\frac{6(6-3)}{2}$

= $\frac{18}{2}$

= 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = $\frac{7(7-3)}{2}$

= $\frac{28}{2}$

= 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = $\frac{30(30-3)}{2}$

= $\frac{810}{2}$

= 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = $\frac{n(n-3)}{2}$

The number of diagonals in a n-gon is $\frac{n(n-3)}{2}$

7 0

2 years ago

I need help finding the area of the fish tank?

diamong [38]

Answer:

A. 83

Step-by-step explanation:

I hope this helps :)

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2 years ago