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Schach [20]
3 years ago
15

In order to qualify for a role in a play, an actor must be taller than 64 inches but shorter than 68 inches. The inequality 64 &

lt; x < 68, where x represents height, can be used to represent the height range. Which is another way of writing the inequality?
Mathematics
2 answers:
Oksanka [162]3 years ago
5 0
It can be written 68 > x > 64.
Oksana_A [137]3 years ago
3 0

Answer:

x \epsilon (64,68)

Step-by-step explanation:

Given that in order to qualify for a role in a play, an actor must be taller than 64 inches but shorter than 68 inches.

The inequality

64 < x < 68,

where x represents height, can be used to represent the height range.

This can also be written in interval form without including end values.

i.e. open brackets will be used to denote intervals.

x \epsilon (64,68)

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A surveyor leave her base camp and drive 42 km on a bearing of 032, she then drive 28km on a bearing of 154.How far is she then
aleksklad [387]

Answer:

Step-by-step explanation:

The scenario is represented in the attached photo. Triangle ABC is formed. AB represents her distance from her base camp. We would determine BC by applying the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and B is the angle corresponding to b. It becomes

AB² = AC² + BC² - 2(AC × BC)CosC

AB² = 42² + 28² - 2(42 × 28)Cos58

AB² = 1764 + 784 - 2(1176Cos58)

AB² = 2548 - 1246.37 = 1301.63

AB = √1301.63

AB = 36.08 km

To find the bearing, we would determine angle B by applying sine rule

AB/SinC = AC/SinB

36.08/Sin58 = 42/SinB

Cross multiplying, it becomes

36.08SinB = 42Sin58

SinB = 42Sin58/36.08 = 0.987

B = Sin^-1(0.987)

B = 81°

Therefore, her bearing from the base camp is

360 - 81 = 279°

8 0
3 years ago
28) Find the circumference of a circle with a diameter of 2.5 inches. (it = 3.14)
antoniya [11.8K]

Answer: Circumference = 7.85 inches

Concept:

Here, we need to know the idea of circumference.

The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.

Circumference = 2πr

r = radius

π = constant

Solve:

<u>Given information</u>

r = (1/2) d = (1/2) (2.5) = 1.25 inches

π = 3.14

<u>Given formula</u>

Circumference = 2πr

<u>Substitute values into the formula</u>

Circumference = 2 · (3.14) · (1.25)

<u>Simplify by multiplication</u>

Circumference = (2.5) · (2.14)

Circumference = \boxed {7.85 inches}

Hope this helps!! :)

Please let me know if you have any questions

3 0
3 years ago
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