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sesenic [268]
3 years ago
15

Solve for a a^2+17=42?

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

We are given the following equation:

a^2+17=42

Subtract both sides by 17

a^2=25

Take the positive/negative square root of both sides

a=\pm5

This should be your answer. Let me know if you have any questions, thanks!

You might be interested in
A circle is centered on point B, Points A, C and D lie on its circumference. if ABC measures 46 degrees, what does ADC measures?
den301095 [7]
Answer: 23 degrees

---------------------------------------
---------------------------------------

Explanation:

Using the inscribed angle theorem we can connect the central angle ABC and the inscribed angle ADC. The reason why is because they both cut off the minor arc AC

Angle ABC is given to be 46 degrees, the formula we use is shown below

central angle = 2*(inscribed angle)
angle ABC = 2*(angle ADC)
46 = 2*(angle ADC)
46/2 = 2*(angle ADC)/2 ... divide both sides by 2
23 = angle ADC
angle ADC = 23 degrees

5 0
3 years ago
PLS HELP I WILL GIVE HRAINLIEST JUST PLSSSSSSSS
olchik [2.2K]
There will have to be 5 because of the 4
7 0
3 years ago
HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-
Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

f(x) =2x^3-9x^2+13x-6

If x+1 is a factor , then f(-1) must evaluate to zero.

f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6

f( - 1) =2( - 1)-9( 1)+13( - 1)-6

f( - 1) = - 2-9 - 13-6

f( - 1) = -11 - 19

f( - 1) = - 30

Since f(-1) is not equal to zero, x+1 is not a factor of

f(x) =2x^3-9x^2+13x-6

6 0
3 years ago
What is the answer to these two
Serggg [28]

Answer:

1.) m<6 and m<8=142, m<9=38

2.) m<7 and m<9=66, m<8=114

note: brainliest would be appreciated.

Step-by-step explanation:

8 0
3 years ago
Translate the given phrase into an algebraic expression and simplify if possible: the difference of −5 and −30.
lawyer [7]

Answer:

IIaI-IbII

Step-by-step explanation:

II-30I-I-5II=

I30-5I=

I25I=

25

II-5I-I-30II=

I5-30I=

I-25I=

25

8 0
2 years ago
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