Answer:
A
Step-by-step explanation:
The formula used for this type of question is
so as long as you don't change anything else (like r), changing m will increase the force. Both of the last 2 answers look like they might be feasible, but they are not. The attraction increases.
So the answer is A
Answer:
2,893
Step-by-step explanation:
divide 3 by 8679
hope this helps:)
Answer:
All real numbers less than or equal to
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
Let the required number be x
![\huge {x}^{9} \div {x}^{6} = 125 \\ \\ \huge {x}^{9 - 6} = 125 \\ \\ \huge {x}^{3} = 125 \\ \\ \huge x = \sqrt[3]{125} \\ \\ \huge x = \sqrt[3]{ {5}^{3} } \\ \\ \huge \red{ x = 5}](https://tex.z-dn.net/?f=%20%5Chuge%20%7Bx%7D%5E%7B9%7D%20%20%5Cdiv%20%20%7Bx%7D%5E%7B6%7D%20%20%3D%20125%20%5C%5C%20%20%5C%5C%20%5Chuge%20%7Bx%7D%5E%7B9%20-%206%7D%20%20%3D%20125%20%5C%5C%20%20%5C%5C%20%5Chuge%20%7Bx%7D%5E%7B3%7D%20%20%3D%20125%20%5C%5C%20%20%5C%5C%20%5Chuge%20x%20%3D%20%20%5Csqrt%5B3%5D%7B125%7D%20%5C%5C%20%20%5C%5C%20%5Chuge%20x%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%5Chuge%20%5Cred%7B%20x%20%3D%205%7D)
To get a feel for where those two radicals fall on the number line, take a look at the perfect square roots they fall between. Both sqrt(7) and sqrt(8) fall between the perfect square roots sqrt(4) and sqrt(9); since sqrt(4) = 2 and sqrt(9) = 3, we know that sqrt(7) and sqrt(8) are somewhere in between 2 and 3. This means we know that sqrt(7) > 2. What about sqrt(8)/2 though? Well, sqrt(4)/2 = 2/2 = 1, and sqrt(9)/2 = 3/2 = 1 1/2, so sqrt(8)/2 has to be between 1 and 1 1/2, both of which are less than 2. Putting those all in order:
sqrt(8)/2, 2, sqrt(7)
