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2 years ago

The half-life of rhodium, Rh-106, is about 30 seconds. You start with 500 grams.

1 answer:

7 0

I think the logical question for this would be to find the reaction rate constant, k, for radioactive decay of Rhodium. The general formula is:

ln A/A₀ = -kt,
where
A is the amount of substance after time t,
A₀ is the original amount of substance
t is the time

After 30 s, the amount of Rhodium would be in half. So, A/A₀ = 1/2

ln(1/2) = -k(30 s)
k = 0.023 s⁻¹

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The vagabonds were 200 miles apart at 2 p.M and were headed toward each other if they met at 6 p.M and one was traveling 10 mile

muminat

Answer:

The answer is 200

Step-by-step explanation:

To solve the question given, let us recall the following,

Let r4=200 miles apart

r=50 mph combined speed

Where

2f+10=50

2f=40

f=20

f+10=30

or we can express it in another way,

which is

f x4+(f+10)x 4=200

f x4+f x4+40=200

8f+40=200

Then

8f is =160

f=20

f+10=30

Therefore,

4x 20+4 x 30=200

80+120=200

200=200

8 0

2 years ago

Read 2 more answers

Find the sum of the following ap .1) 1/15, 1/12, 1/10,....,to 11 terms

sertanlavr [38]

Answer:

33/20

Step-by-step explanation:

1/12 - 1/15 = 5/60 - 4/60 = 1/60

d = 1/60

a_n = a_1 + d(n - 1)

a_11 = 1/15 + (1/60)(11 - 1)

a_11 = 1/15 + 1/6

a_11 = 4/60 + 10/60

a_11 = 14/60

a_11 = 7/30

a_12 = 14/60 + 1/60

a_12 = 15/60

a_12 = 1/4

s_n = n(a_1 + a_n)/2

s_11 = 11(1/15 + 7/30)/2

s_11 = 11(2/30 + 7/30)/2

s_11 = 11(9/30)/2

s_11 = 99/60

s_11 = 33/20

8 0

3 years ago

Pllllllzzzzzzzzz help me

Fed [463]

Answer:

for the first one he will get $51

the second one is £2.70

Step-by-step explanation:

8 0

3 years ago

Solve by factoring x^2-10=9x

BabaBlast [244]

Answer:

x=10

Step-by-step explanation:

x^2 - 10 - (9x) = 0

x^2 - 9x - 10 = 0

(x - 10) + (x + 1) = 0

x= 10

x = -1

4 0

2 years ago

I need help on 1 & 2

Anon25 [30]

Answer:

1 - Avenue A is perpendicular to South St.

2 - 70°

Step-by-step explanation:

1 - North, Center, and South St. are parallel lines. Therefore Ave A will be perpendicular to the three lines.

2 - Ave B and Center street forms a 70° angle. Since Center and South St. are parallel lines, they have corresponding angles. Therefore, Ave B and South St also form a 70° angle. The same is true for Ave B and North St.

3 0

3 years ago