Pluto is the last planet discovered in our solar system.
Answer:
The west component of the given vector is - 42.548 meters.
Explanation:
We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

Where:
- Horizontal component of vector distance, measured in meters.
- Vertical component of vector distance, measured in meters.
Let suppose that east and north have positive signs, then we get the following expression:
![(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-45%5Ccdot%20%5Ccos%2019%5E%7B%5Ccirc%7D%2C%20-45%5Ccdot%20%5Csin%2019%5E%7B%5Ccirc%7D%29%5C%2C%5Bm%5D)
![(x, y) = (-42.548,-14.651)\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-42.548%2C-14.651%29%5C%2C%5Bm%5D)
The west component corresponds to the first component of the ordered pair. That is to say:

The west component of the given vector is - 42.548 meters.
Yes yes sir yes I’ll dm is the day I get that I wanna go home and get my
Average speed is defined by the following formula

here
D = total distance that an object move from its initial position to final position
t = total time of the motion
so here we will say that there is no such relation between initial or final speed or we can say maximum or minimum speed of object with average speed of object.
We only need to find the total distance and total time of motion in order to find the average speed
here we can see many examples like let say an object moves with speed v1 for time t1 and then with speed v2 for time t2 then here average speed is given as

since we know that distance covered is product of speed and time
that's why we used above equation for finding total distance
now the average speed will be

so this is how we can find the average speed for above motion
so average speed is always between maximum and minimum speed any value in-between.
It is neither the maximum value nor it is minimum value
Answer:
the distance between interference fringes increases
Explanation:
For double-slit interference, the distance of the m-order maximum from the centre of the distant screen is

where
is the wavelength, D is the distance of the screen, and d the distance between the slits. The distance between two consecutive fringes (m and m+1) will be therefore

and we see that it inversely proportional to the distance between the slits, d. Therefore, when the separation between the slits decreases, the distance between the interference fringes increases.